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Question
Three chairs and two tables cost ₹ 1850. Five chairs and three tables cost ₹2850. Find the cost of four chairs and one table by using matrices
Solution
Let the cost of 1 chair and 1 table be ₹ x and ₹ y respectively.
According to the first condition,
3x + 2y = 1850
According to the second condition,
5x + 3y = 2850
Matrix form of the above system of equations is
`[(3, 2),(5, 3)] [(x),(y)] = [(1850),(2850)]`
Applying R2 → 3R2 − 5R1, we get
`[(3, 2),(0, -1)] [(x),(y)] = [(1850),(-700)]`
∴ By equality of matrices, we get
3x + 2y = 1850 .......(i)
−y = −700
i.e., y = 700
Substituting y = 700 in equation (i), we get
3x + 2(700) = 1850
∴ 3x = 450
∴ x = 150
∴ The cost of four chairs = 4 × 150 = ₹ 600
∴ The cost of four chairs and one table is ₹ 600 + ₹ 700 = ₹ 1300.
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