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Expand the expression: (2x – 3)6 - Mathematics

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प्रश्न

Expand the expression: (2x – 3)6

योग

उत्तर

By using Binomial Theorem, the expression (2x – 3)can be expanded as

`(2x - 3)^6 = (2x)^6 +  ^6C_1 (2x)^5 (-  3) +  ^6C_2 (2x)^4 (-3)^2 +  ^6C_3 (2x)^3 (-  3)^3  +  ^6C_4 (2x)^2 (-  3)^4  + ^6C_5 (2x)^1  (-  3)^5  + (-  3)^6`

= `64x^6 + 6.32x^2 (-3) + 15. 16x^4 . 9 + 20.8 x^3 (- 27) + 15.4x^2 . 81 + 6.2x (-  243) + 729`

= `64x^6 - 576x^5 + 2160  x^4 - 4320x^2 + 4860x^2  - 2916x  + 729`

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अध्याय 8: Binomial Theorem - Exercise 8.1 [पृष्ठ १६६]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 8 Binomial Theorem
Exercise 8.1 | Q 3 | पृष्ठ १६६

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