हिंदी

Find the Sum to N Terms of the Series Whose Nth Terms is Given by (2n – 1)2 - Mathematics

Advertisements
Advertisements

प्रश्न

Find the sum to n terms of the series whose nth terms is given by (2n – 1)2

उत्तर

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Sequences and Series - Exercise 9.4 [पृष्ठ १९६]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
अध्याय 9 Sequences and Series
Exercise 9.4 | Q 10 | पृष्ठ १९६

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the sum to n terms of the series 1 × 2 × 3 + 2 × 3 × 4 + 3 × 4 × 5 + …


Find the sum to n terms of the series `1/(1xx2) + 1/(2xx3)+1/(3xx4)+ ...`


Find the sum to n terms of the series 3 × 8 + 6 × 11 + 9 × 14 +…


Find the sum to n terms of the series 12 + (12 + 22) + (12 + 22 + 32) + …


Find the sum to n terms of the series whose nth term is given by n (n + 1) (n + 4).


Show that  `(1xx2^2 + 2xx3^2 + ...+nxx(n+1)^2)/(1^2 xx 2 + 2^2 xx3 + ... + n^2xx (n+1))` = `(3n + 5)/(3n + 1)`


22 + 42 + 62 + 82 + ...


1.2.4 + 2.3.7 +3.4.10 + ...


1 + (1 + 2) + (1 + 2 + 3) + (1 + 2 + 3 + 4) + ...


1 × 2 + 2 × 3 + 3 × 4 + 4 × 5 + ...


3 × 12 + 5 ×22 + 7 × 32 + ...


Find the sum of the series whose nth term is:

2n2 − 3n + 5


Find the sum of the series whose nth term is:

(2n − 1)2


Write the sum of the series 12 − 22 + 32 − 42 + 52 − 62 + ... + (2n − 1)2 − (2n)2.


1 + 3 + 7 + 13 + 21 + ...


1 + 3 + 6 + 10 + 15 + ...


\[\frac{1}{1 . 4} + \frac{1}{4 . 7} + \frac{1}{7 . 10} + . . .\]


The value of  \[\sum^n_{r = 1} \left\{ (2r - 1) a + \frac{1}{b^r} \right\}\] is equal to


Write the sum of 20 terms of the series \[1 + \frac{1}{2}(1 + 2) + \frac{1}{3}(1 + 2 + 3) + . . . .\]


Let Sn denote the sum of the cubes of first n natural numbers and sn denote the sum of first n natural numbers. Then, write the value of \[\sum^n_{r = 1} \frac{S_r}{s_r}\] .


The sum to n terms of the series \[\frac{1}{\sqrt{1} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{7}} + . . . . + . . . .\]  is


The sum of the series

\[\frac{1}{\log_2 4} + \frac{1}{\log_4 4} + \frac{1}{\log_8 4} + . . . . + \frac{1}{\log_2^n 4}\] is


If \[1 + \frac{1 + 2}{2} + \frac{1 + 2 + 3}{3} + . . . .\] to n terms is S, then S is equal to


The sum of 10 terms of the series \[\sqrt{2} + \sqrt{6} + \sqrt{18} +\] .... is

 

The sum of the series 12 + 32 + 52 + ... to n terms is 


Write the sum to n terms of a series whose rth term is r + 2r.

 

If \[\sum^n_{r = 1} r = 55, \text{ find }  \sum^n_{r = 1} r^3\] .

 


2 + 5 + 10 + 17 + 26 + ...

 

Find the sum of the series (33 – 23) + (53 – 43) + (73 – 63) + … to n terms


Let Sn denote the sum of the cubes of the first n natural numbers and sn denote the sum of the first n natural numbers. Then `sum_(r = 1)^n S_r/s_r` equals ______.


The sum of all natural numbers 'n' such that 100 < n < 200 and H.C.F. (91, n) > 1 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×
Our website is made possible by ad-free subscriptions or displaying online advertisements to our visitors.
If you don't like ads you can support us by buying an ad-free subscription or please consider supporting us by disabling your ad blocker. Thank you.