हिंदी

Find the Sum To N Terms of the Series Whose Nth Terms is Given By N2 + 2n - Mathematics

Advertisements
Advertisements

प्रश्न

Find the sum to n terms of the series whose nth terms is given by n2 + 2n

उत्तर

an = n2 + 2n

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Sequences and Series - Exercise 9.4 [पृष्ठ १९६]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
अध्याय 9 Sequences and Series
Exercise 9.4 | Q 9 | पृष्ठ १९६

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the sum to n terms of the series 1 × 2 + 2 × 3 + 3 × 4 + 4 × 5 + …


Find the sum to n terms of the series 1 × 2 × 3 + 2 × 3 × 4 + 3 × 4 × 5 + …


Find the sum to n terms of the series 3 × 12 + 5 × 22 + 7 × 32 + …


Show that  `(1xx2^2 + 2xx3^2 + ...+nxx(n+1)^2)/(1^2 xx 2 + 2^2 xx3 + ... + n^2xx (n+1))` = `(3n + 5)/(3n + 1)`


1+ 3+ 53 + 73 + ...


1.2.5 + 2.3.6 + 3.4.7 + ...


1.2.4 + 2.3.7 +3.4.10 + ...


1 + (1 + 2) + (1 + 2 + 3) + (1 + 2 + 3 + 4) + ...


Find the sum of the series whose nth term is:

2n2 − 3n + 5


Find the sum of the series whose nth term is:

(2n − 1)2


Write the sum of the series 2 + 4 + 6 + 8 + ... + 2n.


Write the sum of the series 12 − 22 + 32 − 42 + 52 − 62 + ... + (2n − 1)2 − (2n)2.


1 + 3 + 7 + 13 + 21 + ...


4 + 6 + 9 + 13 + 18 + ...


\[\frac{1}{1 . 4} + \frac{1}{4 . 7} + \frac{1}{7 . 10} + . . .\]


\[\frac{1}{1 . 6} + \frac{1}{6 . 11} + \frac{1}{11 . 14} + \frac{1}{14 . 19} + . . . + \frac{1}{(5n - 4) (5n + 1)}\]


If ∑ n = 210, then ∑ n2 =


If Sn = \[\sum^n_{r = 1} \frac{1 + 2 + 2^2 + . . . \text { Sum to r terms }}{2^r}\], then Sn is equal to


Write the 50th term of the series 2 + 3 + 6 + 11 + 18 + ...


Let Sn denote the sum of the cubes of first n natural numbers and sn denote the sum of first n natural numbers. Then, write the value of \[\sum^n_{r = 1} \frac{S_r}{s_r}\] .


The sum to n terms of the series \[\frac{1}{\sqrt{1} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{7}} + . . . . + . . . .\]  is


The sum of 10 terms of the series \[\sqrt{2} + \sqrt{6} + \sqrt{18} +\] .... is

 

The sum of the series \[\frac{2}{3} + \frac{8}{9} + \frac{26}{27} + \frac{80}{81} +\] to n terms is


If the sum of first n even natural numbers is equal to k times the sum of first n odd natural numbers, then write the value of k.


2 + 5 + 10 + 17 + 26 + ...

 

Find the natural number a for which ` sum_(k = 1)^n f(a + k)` = 16(2n – 1), where the function f satisfies f(x + y) = f(x) . f(y) for all natural numbers x, y and further f(1) = 2.


Find the sum of the series (33 – 23) + (53 – 43) + (73 – 63) + … to n terms


If |x| < 1, |y| < 1 and x ≠ y, then the sum to infinity of the following series:

(x + y) + (x2 + xy + y2) + (x3 + x2y + xy2 + y3) + .... is ______.


The sum of all natural numbers 'n' such that 100 < n < 200 and H.C.F. (91, n) > 1 is ______.


The sum `sum_(k = 1)^20k 1/2^k` is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×