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If S1 be the sum of (2n + 1) terms of an A.P. and S2 be the sum of its odd terms, then prove that: S1 : S2 = (2n + 1) : (n + 1). - Mathematics

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प्रश्न

If S1 be the sum of (2n + 1) terms of an A.P. and S2 be the sum of its odd terms, then prove that: S1 : S2 = (2n + 1) : (n + 1).

योग

उत्तर

To prove: S1 : S2 = (2n + 1) : (n + 1)

We know that the sum of AP is given by the formula:

`S = n/2(2a + (n - 1)d)`

Substituting the values in the above equation,

`S_1 = (2n + 1)/2 (2a + 2nd)`

For the sum of odd terms, it is given by,

`S_2 = a_1 + a_3 + a_5 + .....a_(2n) + 1`

`S_2 = a + a + 2d + a + 4d + .... + a + 2nd`

`S_2 = (n + 1)a + n (n + 1)d`

`S_2 = (n + 1)(a + nd)`

Hence,

`S_1 : S_2 = (2n + 1)/(n + 1)`

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अध्याय 19: Arithmetic Progression - Exercise 19.4 [पृष्ठ ३१]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 19 Arithmetic Progression
Exercise 19.4 | Q 30 | पृष्ठ ३१

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