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Solve the following differential equation. dydx=x2y+y - Mathematics and Statistics

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प्रश्न

Solve the following differential equation.

dydx=x2y+y

योग

उत्तर

dydx=x2y+y=(x2+1)y

1ydy=(x2+1)dx

Integrating on both sides, we get

1ydy =(x2+1)dx

log |y|=x33+x+c

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अध्याय 8: Differential Equation and Applications - Exercise 8.3 [पृष्ठ १६५]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] 12 Standard HSC Maharashtra State Board
अध्याय 8 Differential Equation and Applications
Exercise 8.3 | Q 1.1 | पृष्ठ १६५

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