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प्रश्न
Solve the following differential equation.
`dy/dx = x^2 y + y`
उत्तर
`dy/dx = x^2 y + y = (x^2 +1)y`
∴ `1/y dy = (x^2 + 1)dx`
Integrating on both sides, we get
` int 1/y dy = int (x^2+1) dx`
∴ `log | y | = x^3/3 + x + c`
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