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प्रश्न
The Cartestation equation of line is `(x-6)/2=(y+4)/7=(z-5)/3` find its vector equation.
उत्तर
`(x-6)/2=(y+4)/7=(z-5)/3`
Line is passing through the point (6,–4,5) with drs 2, 7, 3
Equation of line in vector form is
`vecr=(6veci-4vecj+5veck)+lambda(2 veci+7 vecj+3vec k)`
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