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प्रश्न
(ax2 + cot x)(p + q cos x)
उत्तर
`d/(dx) (ax^2 + cot x)(p + q cos x)`
= `(ax^2 + cot x) d/(dx) (p + q cos x) + (p + q cos x) d/(dx) (ax^2 + cot x)` .....[Using Product Rule]
= `(ax^2 + cot x) (-q sin x) + (p + q cos x) (2ax - "cosec"^2x)`
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