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प्रश्न
Evaluate `int (3"x"^2 - 5)^2` dx
उत्तर
Let I = `int (3"x"^2 - 5)^2` dx
`= int (9"x"^4 - 30"x"^2 + 25)` dx
`= 9 int "x"^4 "dx" - 30 int "x"^2 "dx" + 25 int "dx"`
`= 9 ("x"^5/5) - 30 ("x"^3/3)` + 25x + c
∴ I = `9/5 "x"^5 - 10"x"^3 + 25"x" + "c"`
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