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प्रश्न
Evaluate the following integrals : `int (cos2x)/(sin^2x.cos^2x)dx`
उत्तर
`int (cos2x)/(sin^2x.cos^2x)dx`
= `int(cos^2x - sin^2x)/(sin^2x.cos^2x)dx`
= `int(1/sin^2x - 1/cos^2x)dx`
= `int "cosec"^2x dx - int sec^2 x dx`
= – cot x – tan x + c.
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