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प्रश्न
Evaluate `int e^x [(cosx - sin x)/sin^2 x]dx`
उत्तर
`I = inte^x [cosx/sin^2x - sinx/sin^2x]dx`
`= int e^x[(cotx.cosecx, -cosecx),(f'(x), f(x))]`
∵ `int e^x[f(x) + f'(x)]dx = e^x f(x) + C`
`:. I = -e^x.cosec x + C`
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