Advertisements
Advertisements
प्रश्न
If \[\left[ x \right]^2 - 5\left[ x \right] + 6 = 0\], where [.] denotes the greatest integer function, then
पर्याय
(a) x ∈ [3, 4]
(b) x ∈ (2, 3]
(c) x ∈ [2, 3]
(d) x ∈ [2, 4)
उत्तर
The given equation is \[\left[ x \right]^2 - 5\left[ x \right] + 6 = 0\]
\[\left[ x \right]^2 - 5\left[ x \right] + 6 = 0\]
\[ \Rightarrow \left[ x \right]^2 - 3\left[ x \right] - 2\left[ x \right] + 6 = 0\]
\[ \Rightarrow \left[ x \right]\left( \left[ x \right] - 3 \right) - 2\left( \left[ x \right] - 3 \right) = 0\]
\[ \Rightarrow \left( \left[ x \right] - 2 \right)\left( \left[ x \right] - 3 \right) = 0\]
\[\Rightarrow \left[ x \right] - 2 = 0 \text{ or } \left[ x \right] - 3 = 0\]
\[ \Rightarrow \left[ x \right] = 2\text{ or } \left[ x \right] = 3\]
⇒ x ∈ [2, 3) or x ∈ [3, 4)
⇒ x ∈ [2, 4)
APPEARS IN
संबंधित प्रश्न
find: f(1), f(−1), f(0) and f(2).
If f : R → R be defined by f(x) = x2 + 1, then find f−1 [17] and f−1 [−3].
If \[f\left( x \right) = \frac{1}{1 - x}\] , show that f[f[f(x)]] = x.
If f(x) = (a − xn)1/n, a > 0 and n ∈ N, then prove that f(f(x)) = x for all x.
Let f and g be two real functions defined by \[f\left( x \right) = \sqrt{x + 1}\] and \[g\left( x \right) = \sqrt{9 - x^2}\] . Then, describe function:
(vi) \[2f - \sqrt{5} g\]
Write the range of the function f(x) = cos [x], where \[\frac{- \pi}{2} < x < \frac{\pi}{2}\] .
If f : Q → Q is defined as f(x) = x2, then f−1 (9) is equal to
If x ≠ 1 and \[f\left( x \right) = \frac{x + 1}{x - 1}\] is a real function, then f(f(f(2))) is
Let A = {x ∈ R : x ≠ 0, −4 ≤ x ≤ 4} and f : A ∈ R be defined by \[f\left( x \right) = \frac{\left| x \right|}{x}\] for x ∈ A. Then th (is
If f : R → R and g : R → R are defined by f(x) = 2x + 3 and g(x) = x2 + 7, then the values of x such that g(f(x)) = 8 are
If f(x) = sin [π2] x + sin [−π]2 x, where [x] denotes the greatest integer less than or equal to x, then
If f(m) = m2 − 3m + 1, find f(−3)
If f(x) = `{(x^2 + 3"," x ≤ 2),(5x + 7"," x > 2):},` then find f(3)
If f(x) = `{(x^2 + 3"," x ≤ 2),(5x + 7"," x > 2):},` then find f(2)
Find the domain and range of the following function.
f(x) = 7x2 + 4x − 1
Find the domain and range of the follwoing function.
h(x) = `sqrt(x + 5)/(5 + x)`
Express the area A of circle as a function of its radius r
Express the following exponential equation in logarithmic form
`9^(3/2)` = 27
Express the following exponential equation in logarithmic form
e–x = 6
Express the following logarithmic equation in exponential form
ln e = 1
Find the domain of f(x) = log10 (x2 − 5x + 6)
Write the following expression as sum or difference of logarithm
In `[(root(3)(x - 2)(2x + 1)^4)/((x + 4)sqrt(2x + 4))]^2`
Solve for x.
x + log10 (1 + 2x) = x log10 5 + log10 6
If f(x) = 3x + 5, g(x) = 6x − 1, then find (fg) (3)
If f(x) = 3x + 5, g(x) = 6x − 1, then find `("f"/"g") (x)` and its domain
Answer the following:
If f(x) = ax2 + bx + 2 and f(1) = 3, f(4) = 42, find a and b
Answer the following:
Let f : R → R be given by f(x) = x + 5 for all x ∈ R. Draw its graph
Answer the following:
If `log ((x - y)/5) = 1/2 logx + 1/2 log y`, show that x2 + y2 = 27xy
Answer the following:
Show that `7log (15/16) + 6log(8/3) + 5log (2/5) + log(32/25)` = log 3
Find the range of the following functions given by `|x - 4|/(x - 4)`
Redefine the function which is given by f(x) = `|x - 1| + |1 + x|, -2 ≤ x ≤ 2`
Find the domain of the following functions given by f(x) = `1/sqrt(1 - cos x)`
Find the range of the following functions given by f(x) = 1 – |x – 2|
Find the domain and range of the function f(x) = `1/sqrt(x - 5)`
If f(x) = y = `(ax - b)/(cx - a)`, then prove that f(y) = x.
The domain of the function f defined by f(x) = `sqrt(4 - x) + 1/sqrt(x^2 - 1)` is equal to ______.
The domain and range of real function f defined by f(x) = `sqrt(x - 1)` is given by ______.
The domain of the function f given by f(x) = `(x^2 + 2x + 1)/(x^2 - x - 6)` is ______.