Advertisements
Advertisements
प्रश्न
Sketch the region bounded by the lines 2x + y = 8, y = 2, y = 4 and the Y-axis. Hence, obtain its area using integration.
उत्तर
2x + y = 8, y = 2, y = 4
Required Area = Area of ABDE + Area of BCD
= `int_0^2 (4 - 2)dx + int_2^3 {(8 - 2x) - 2}dx`
= `[2x]_0^2 + [6x - x^2]_2^3`
= 4 + [18 – 9 – 12 + 4]
= 4 + 1
= 5 sq. units.
APPEARS IN
संबंधित प्रश्न
Find the area of the region common to the circle x2 + y2 =9 and the parabola y2 =8x
Find the area lying above the x-axis and under the parabola y = 4x − x2.
Determine the area under the curve y = \[\sqrt{a^2 - x^2}\] included between the lines x = 0 and x = a.
Using integration, find the area of the region bounded by the following curves, after making a rough sketch: y = 1 + | x + 1 |, x = −2, x = 3, y = 0.
Draw a rough sketch of the curve y = \[\frac{\pi}{2} + 2 \sin^2 x\] and find the area between x-axis, the curve and the ordinates x = 0, x = π.
Find the area bounded by the curve y = cos x, x-axis and the ordinates x = 0 and x = 2π.
Find the area of the region {(x, y) : y2 ≤ 8x, x2 + y2 ≤ 9}.
Find the area of the region common to the circle x2 + y2 = 16 and the parabola y2 = 6x.
Find the area bounded by the parabola y2 = 4x and the line y = 2x − 4 By using horizontal strips.
The area bounded by the parabola x = 4 − y2 and y-axis, in square units, is ____________ .
The area of the region bounded by the parabola (y − 2)2 = x − 1, the tangent to it at the point with the ordinate 3 and the x-axis is _________ .
The area bounded by the parabola y2 = 4ax and x2 = 4ay is ___________ .
The area bounded by the curve y = x4 − 2x3 + x2 + 3 with x-axis and ordinates corresponding to the minima of y is _________ .
The area of the region \[\left\{ \left( x, y \right) : x^2 + y^2 \leq 1 \leq x + y \right\}\] is __________ .
Draw a rough sketch of the curve y2 = 4x and find the area of region enclosed by the curve and the line y = x.
Find the area of the region bounded by the parabola y2 = 2x and the straight line x – y = 4.
The area enclosed by the ellipse `x^2/"a"^2 + y^2/"b"^2` = 1 is equal to ______.
Using integration, find the area of the region bounded between the line x = 4 and the parabola y2 = 16x.
Using integration, find the area of the region in the first quadrant enclosed by the line x + y = 2, the parabola y2 = x and the x-axis.
Using integration, find the area of the region `{(x, y): 0 ≤ y ≤ sqrt(3)x, x^2 + y^2 ≤ 4}`
The region bounded by the curves `x = 1/2, x = 2, y = log x` and `y = 2^x`, then the area of this region, is
What is the area of the region bounded by the curve `y^2 = 4x` and the line `x` = 3.
Let T be the tangent to the ellipse E: x2 + 4y2 = 5 at the point P(1, 1). If the area of the region bounded by the tangent T, ellipse E, lines x = 1 and x = `sqrt(5)` is `sqrt(5)`α + β + γ `cos^-1(1/sqrt(5))`, then |α + β + γ| is equal to ______.
Area (in sq.units) of the region outside `|x|/2 + |y|/3` = 1 and inside the ellipse `x^2/4 + y^2/9` = 1 is ______.
The area (in square units) of the region bounded by the curves y + 2x2 = 0 and y + 3x2 = 1, is equal to ______.
Make a rough sketch of the region {(x, y) : 0 ≤ y ≤ x2 + 1, 0 ≤ y ≤ x + 1, 0 ≤ x ≤ 2} and find the area of the region, using the method of integration.
Hence find the area bounded by the curve, y = x |x| and the coordinates x = −1 and x = 1.