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Question
Answer the following:
A function f is defined as f(x) = 4x + 5, for – 4 ≤ x < 0. Find the values of f(–1), f(–2), f(0), if they exist
Solution
f(x) = 4x + 5, – 4 ≤ x < 0
f(–1) = 4(–1) + 5 = –4 + 5 = 1
f(–2) = 4(–2) + 5 = –8 + 5 = –3
x = 0 ∉ domain of f
∴ f(0) does not exist.
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