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Question
Answer the following:
For any base show that log (1 + 2 + 3) = log 1 + log 2 + log 3
Solution
L.H.S. = log (1 + 2 + 3) = log 6
R.H.S. = log 1 + log 2 + log 3
= 0 + log (2 × 3)
= log 6
∴ L.H.S. = R.H.S.
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