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Question
Evaluate: `int_0^1 |x| "d"x`
Solution
`int_0^1 |x| "d"x - int_0^1 x "d"x` ......[|x| = x, x ≥ 0]
= `[x^2/2]_0^(-1)`
= `1/2(1^2 - 0)`
= `1/2`
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