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Question
Evaluate: `int_0^1(x + 1)^2 "d"x`
Solution
`int_0^1(x + 1)^2 "d"x = [(x + 1)^3/3]_0^1`
= `1/3[(1 + 1)^3 - (0 + 1)^3]`
= `1/3(8 -1)`
= `7/3`
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