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Question
Let I1 = `int_"e"^("e"^2) 1/logx "d"x` and I2 = `int_1^2 ("e"^x)/x "d"x` then
Options
I1 = `1/3 "I"_2`
I1 + I2 = 0
I1 = 2I2
I1 = I2
Solution
I1 = I2
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