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Question
Find the principal value of `sec^(-1) (2/sqrt(3))`
Solution
Let `sec^(-1) (2/sqrt3) = y, `
`" Then " sec y = 2/sqrt3= sec y(pi/6)`
We know that the range of the principal value branch of sec−1 is
`[0,pi] - {pi/2}`
`"Then" sec (pi/6) = 2/sqrt3`
Therefore, the principal value of `sec^(-1) (2/sqrt3) "is" pi/6`
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