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Question
For the differential equation, find the general solution:
`cos^2 x dy/dx + y = tan x(0 <= x < pi/2)`
Solution
The given equation is
`cos^2 x dy/dx + y = tan x`
⇒ `dy/dx + (sec^2 x) y = tan x sec^2 x`
Which is a linear equation of the type
`dy/dx + Py = Q`
Here P = sec2 x and Q = tan sec2 x
∴ `I.F. = e^(intsec^2 x dx) = e^(tan x)`
∴ The solution is `y. (I.F.) = int Q. (I.F.) dx + C`
⇒ `y.e^(tan x) = int tan x sec^2 x e^(tan x) dx + C = I + C` ...(1)
Now, `I = int tan x sec^2 xe^(tan x) dx`
Put tan x = t
⇒ sec2 x dx = dt
∴ `I = int t. e^t dt = t. e^t - int (1) e^t dt` ....[Integrating by parts]
`= te^t - e^t = e^t (t - 1)`
`= e^(tan x) (tan x - 1)`
∴ From (1) `y.e^(tan x) = e^(tan x) (tan x - 1) + C`
⇒ ` y = (tan x - 1) + Ce^(-tan x),` Which is the required solution.
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