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Question
If y = elogx then `dy/dx` = ?
Options
`(e^(logx))/x`
`1/x`
0
`1/2`
Solution
`(e^(log x))/x`
Explanation:
y = elogx
Differentiating both sides w.r.t.x, we get
`dy/dx = e^(logx).d/dx`(logx)
= `e^(logx).1/x`
= `(e^(logx))/x`
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