Question

${\displaystyle \frac{{\tan 47}^{\circ }}{{\cot 43}^{\circ }}}$ = 1

Options

• True

• False

Answer 1

This statement is True.

Explanation:

Since, tan(90° – θ) = cot θ

${\displaystyle \frac{{\tan 47}^{\circ }}{{\cot 43}^{\circ }}=\frac{\tan ({90}^{\circ }-{43}^{\circ })}{{\cot 43}^{\circ }}}$

${\displaystyle \frac{{\tan 47}^{\circ }}{{\cot 43}^{\circ }}=\frac{{\cot 43}^{\circ }}{{\cot 43}^{\circ }}}$ = 1

${\displaystyle \frac{{\tan 47}^{\circ }}{{\cot 43}^{\circ }}}$ = 1