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Question
Write the following expression as sum or difference of logarithm
`log ("pq"/"rs")`
Solution
`log ("pq"/"rs")` = log (pq) – log (rs) ...`[log "m"/"n" = log"m" - log"n"]`
= log p + log q – (log r + log s) ...[log mn = log m log n]
= log p + log q – log r – log s
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