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RD Sharma solutions for Mathematics [English] Class 11 chapter 27 - Hyperbola [Latest edition]

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RD Sharma solutions for Mathematics [English] Class 11 chapter 27 - Hyperbola - Shaalaa.com
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Solutions for Chapter 27: Hyperbola

Below listed, you can find solutions for Chapter 27 of CBSE, Karnataka Board PUC RD Sharma for Mathematics [English] Class 11.


Exercise 27.1Exercise 27.2Exercise 27.3
Exercise 27.1 [Pages 13 - 14]

RD Sharma solutions for Mathematics [English] Class 11 27 Hyperbola Exercise 27.1 [Pages 13 - 14]

Exercise 27.1 | Q 1 | Page 13

The equation of the directrix of a hyperbola is x − y + 3 = 0. Its focus is (−1, 1) and eccentricity 3. Find the equation of the hyperbola.

Exercise 27.1 | Q 2.1 | Page 13

Find the equation of the hyperbola whose focus is (0, 3), directrix is x + y − 1 = 0 and eccentricity = 2 .

Exercise 27.1 | Q 2.2 | Page 13

Find the equation of the hyperbola whose focus is (1, 1), directrix is 3x + 4y + 8 = 0 and eccentricity = 2 .

Exercise 27.1 | Q 2.3 | Page 13

Find the equation of the hyperbola whose focus is (1, 1) directrix is 2x + y = 1 and eccentricity = \[\sqrt{3}\].

Exercise 27.1 | Q 2.4 | Page 13

Find the equation of the hyperbola whose focus is (2, −1), directrix is 2x + 3y = 1 and eccentricity = 2 .

Exercise 27.1 | Q 2.5 | Page 13

Find the equation of the hyperbola whose focus is (a, 0), directrix is 2x − y + a = 0 and eccentricity = \[\frac{4}{3}\].

Exercise 27.1 | Q 2.6 | Page 13

Find the equation of the hyperbola whose focus is (2, 2), directrix is x + y = 9 and eccentricity = 2.

Exercise 27.1 | Q 3.1 | Page 13

Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

9x2 − 16y2 = 144

Exercise 27.1 | Q 3.2 | Page 13

Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

16x2 − 9y2 = −144

Exercise 27.1 | Q 3.3 | Page 13

Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

 4x2 − 3y2 = 36

Exercise 27.1 | Q 3.4 | Page 13

Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

 3x2 − y2 = 4 

Exercise 27.1 | Q 3.5 | Page 13

Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

2x2 − 3y2 = 5.

Exercise 27.1 | Q 4 | Page 13

Find the axes, eccentricity, latus-rectum and the coordinates of the foci of the hyperbola 25x2 − 36y2 = 225.

Exercise 27.1 | Q 5.1 | Page 13

Find the centre, eccentricity, foci and directrice of the hyperbola .

16x2 − 9y2 + 32x + 36y − 164 = 0

Exercise 27.1 | Q 5.2 | Page 13

Find the centre, eccentricity, foci and directrice of the hyperbola.

 x2 − y2 + 4x = 0

Exercise 27.1 | Q 5.3 | Page 13

Find the centre, eccentricity, foci and directrice of the hyperbola .

x2 − 3y2 − 2x = 8.

Exercise 27.1 | Q 6.1 | Page 13

Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in  the distance between the foci = 16 and eccentricity = \[\sqrt{2}\].

Exercise 27.1 | Q 6.2 | Page 13

Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in  the  conjugate axis is 5 and the distance between foci = 13 .

Exercise 27.1 | Q 6.3 | Page 13

Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in  the conjugate axis is 7 and passes through the point (3, −2).

Exercise 27.1 | Q 7.1 | Page 14

Find the equation of the hyperbola whose foci are (6, 4) and (−4, 4) and eccentricity is 2.

Exercise 27.1 | Q 7.2 | Page 14

Find the equation of the hyperbola whose vertices are (−8, −1) and (16, −1) and focus is (17, −1).

Exercise 27.1 | Q 7.3 | Page 14

Find the equation of the hyperbola whose  foci are (4, 2) and (8, 2) and eccentricity is 2.

Exercise 27.1 | Q 7.4 | Page 14

Find the equation of the hyperbola whose vertices are at (0 ± 7) and foci at \[\left( 0, \pm \frac{28}{3} \right)\] . 

Exercise 27.1 | Q 7.5 | Page 14

Find the equation of the hyperbola whose vertices are at (± 6, 0) and one of the directrices is x = 4.

Exercise 27.1 | Q 7.6 | Page 14

Find the equation of the hyperbola whose foci at (± 2, 0) and eccentricity is 3/2. 

Exercise 27.1 | Q 8 | Page 14

Find the eccentricity of the hyperbola, the length of whose conjugate axis is \[\frac{3}{4}\] of the length of transverse axis.

Exercise 27.1 | Q 9.1 | Page 14

Find the equation of the hyperboala whose focus is at (5, 2), vertex at (4, 2) and centre at (3, 2).

Exercise 27.1 | Q 9.2 | Page 14

Find the equation of the hyperboala whose focus is at (4, 2), centre at (6, 2) and e = 2.

Exercise 27.1 | Q 10 | Page 14

If P is any point on the hyperbola whose axis are equal, prove that SP. S'P = CP2.

Exercise 27.1 | Q 11.01 | Page 14

Find the equation of the hyperbola satisfying the given condition :

vertices (± 2, 0), foci (± 3, 0)

Exercise 27.1 | Q 11.02 | Page 14

Find the equation of the hyperbola satisfying the given condition :

 vertices (0, ± 5), foci (0, ± 8)

Exercise 27.1 | Q 11.03 | Page 14

Find the equation of the hyperbola satisfying the given condition :

vertices (0, ± 3), foci (0, ± 5)

Exercise 27.1 | Q 11.04 | Page 14

Find the equation of the hyperbola satisfying the given condition :

 foci (± \[3\sqrt{5}\] 0), the latus-rectum = 8

Exercise 27.1 | Q 11.05 | Page 14

Find the equation of the hyperbola satisfying the given condition :

 foci (0, ± 13), conjugate axis = 24

Exercise 27.1 | Q 11.06 | Page 14

find the equation of the hyperbola satisfying the given condition:

 foci (± \[3\sqrt{5}\]  0), the latus-rectum = 8

Exercise 27.1 | Q 11.07 | Page 14

(vii)  find the equation of the hyperbola satisfying the given condition:

foci (± 4, 0), the latus-rectum = 12

Exercise 27.1 | Q 11.08 | Page 14

find the equation of the hyperbola satisfying the given condition:

 vertices (± 7, 0), \[e = \frac{4}{3}\]

Exercise 27.1 | Q 11.09 | Page 14

Find the equation of the hyperbola satisfying the given condition:

 foci (0, ± \[\sqrt{10}\], passing through (2, 3).

Exercise 27.1 | Q 11.1 | Page 14

find the equation of the hyperbola satisfying the given condition:

foci (0, ± 12), latus-rectum = 36

Exercise 27.1 | Q 12 | Page 14

If the distance between the foci of a hyperbola is 16 and its ecentricity is \[\sqrt{2}\],then obtain its equation.

Exercise 27.1 | Q 13 | Page 14

Show that the set of all points such that the difference of their distances from (4, 0) and (− 4,0) is always equal to 2 represents a hyperbola.

Exercise 27.2 [Page 18]

RD Sharma solutions for Mathematics [English] Class 11 27 Hyperbola Exercise 27.2 [Page 18]

Exercise 27.2 | Q 1 | Page 18

Write the eccentricity of the hyperbola 9x2 − 16y2 = 144.

Exercise 27.2 | Q 2 | Page 18

Write the eccentricity of the hyperbola whose latus-rectum is half of its transverse axis.

Exercise 27.2 | Q 3 | Page 18

Write the coordinates of the foci of the hyperbola 9x2 − 16y2 = 144.

Exercise 27.2 | Q 4 | Page 18

Write the equation of the hyperbola of eccentricity \[\sqrt{2}\],  if it is known that the distance between its foci is 16.

Exercise 27.2 | Q 5 | Page 18

If the foci of the ellipse \[\frac{x^2}{16} + \frac{y^2}{b^2} = 1\] and the hyperbola \[\frac{x^2}{144} - \frac{y^2}{81} = \frac{1}{25}\] coincide, write the value of b2.

Exercise 27.2 | Q 6 | Page 18

Write the length of the latus-rectum of the hyperbola 16x2 − 9y2 = 144.

Exercise 27.2 | Q 7 | Page 18

If the latus-rectum through one focus of a hyperbola subtends a right angle at the farther vertex, then write the eccentricity of the hyperbola.

Exercise 27.2 | Q 8 | Page 18

Write the distance between the directrices of the hyperbola x = 8 sec θ, y = 8 tan θ.

Exercise 27.2 | Q 9 | Page 18

Write the equation of the hyperbola whose vertices are (± 3, 0) and foci at (± 5, 0).

Exercise 27.2 | Q 10 | Page 18

If e1 and e2 are respectively the eccentricities of the ellipse \[\frac{x^2}{18} + \frac{y^2}{4} = 1\]

and the hyperbola \[\frac{x^2}{9} - \frac{y^2}{4} = 1\] then write the value of 2 e12 + e22.

Exercise 27.3 [Pages 18 - 20]

RD Sharma solutions for Mathematics [English] Class 11 27 Hyperbola Exercise 27.3 [Pages 18 - 20]

Exercise 27.3 | Q 1 | Page 18

Equation of the hyperbola whose vertices are (± 3, 0) and foci at (± 5, 0), is

  • 16x2 − 9y2 = 144

  • 9x2 − 16y2 = 144

  •  25x2 − 9y= 225

  • 9x2 − 25y2 = 81

Exercise 27.3 | Q 2 | Page 18

If e1 and e2 are respectively the eccentricities of the ellipse \[\frac{x^2}{18} + \frac{y^2}{4} = 1\] and the hyperbola \[\frac{x^2}{9} - \frac{y^2}{4} = 1\] , then the relation between e1 and e2 is

  •  3 e12 + e22 = 2

  •  e12 + 2 e22 = 3

  • e12 + e22 = 3

  • e12 + 3 e22 = 2

Exercise 27.3 | Q 3 | Page 19

The distance between the directrices of the hyperbola x = 8 sec θ, y = 8 tan θ, is

  • \[8\sqrt{2}\]

  • \[16\sqrt{2}\]

  • \[4\sqrt{2}\]

  • \[6\sqrt{2}\]

Exercise 27.3 | Q 4 | Page 19

The equation of the conic with focus at (1, 1) directrix along x − y + 1 = 0 and eccentricity \[\sqrt{2}\] is

  • xy = 1

  •  2xy + 4x − 4y − 1= 0

  • x2 − y2 = 1

  • 2xy − 4x + 4y + 1 = 0

Exercise 27.3 | Q 5 | Page 19

The eccentricity of the conic 9x2 − 16y2 = 144 is 

  • \[\frac{5}{4}\]

  • \[\frac{4}{3}\]

  • \[\frac{4}{5}\]

  • \[\sqrt{7}\]

Exercise 27.3 | Q 6 | Page 19

A point moves in a plane so that its distances PA and PB from two fixed points A and B in the plane satisfy the relation PA − PB = k (k ≠ 0), then the locus of P is

  •  a hyperbola

  •  a branch of the hyperbola

  • a parabola

  • an ellipse

Exercise 27.3 | Q 7 | Page 19

The eccentricity of the hyperbola whose latus-rectum is half of its transverse axis, is 

  • \[\frac{1}{\sqrt{2}}\]

  • \[\sqrt{\frac{2}{3}}\]

  • \[\sqrt{\frac{3}{2}}\]

  •  none of these.

Exercise 27.3 | Q 8 | Page 19

The eccentricity of the hyperbola x2 − 4y2 = 1 is 

  • \[\frac{\sqrt{3}}{2}\]

  • \[\frac{\sqrt{5}}{2}\]

  • \[\frac{2}{\sqrt{3}}\]

  • \[\frac{2}{\sqrt{5}}\]

Exercise 27.3 | Q 9 | Page 19

The difference of the focal distances of any point on the hyperbola is equal to

  • length of the conjugate axis

  •  eccentricity

  • length of the transverse axis

  • Latus-rectum

Exercise 27.3 | Q 10 | Page 19

The foci of the hyperbola 9x2 − 16y2 = 144 are

  • (± 4, 0)

  • (0, ± 4)

  •  (± 5, 0)

  • (0, ± 5)

Exercise 27.3 | Q 11 | Page 19

The distance between the foci of a hyperbola is 16 and its eccentricity is \[\sqrt{2}\], then equation of the hyperbola is

  •  x2 + y2 = 32

  • x2 − y2 = 16

  • x2 + y2 = 16

  •  x2 − y2 = 32

Exercise 27.3 | Q 12 | Page 19

If e1 is the eccentricity of the conic 9x2 + 4y2 = 36 and e2 is the eccentricity of the conic 9x2 − 4y2 = 36, then

  • e12 − e22 = 2

  • 2 < e22 − e12 < 3

  • e22 − e12 = 2

  • e22 − e12 > 3

Exercise 27.3 | Q 13 | Page 19

If the eccentricity of the hyperbola x2 − y2 sec2α = 5 is \[\sqrt{3}\]  times the eccentricity of the ellipse x2 sec2 α + y2 = 25, then α =

  • \[\frac{\pi}{6}\]

  • \[\frac{\pi}{4}\]

  • \[\frac{\pi}{3}\]

  • \[\frac{\pi}{2}\]

Exercise 27.3 | Q 14 | Page 19

The equation of the hyperbola whose foci are (6, 4) and (−4, 4) and eccentricity 2, is

  • \[\frac{(x - 1 )^2}{25/4} - \frac{(y - 4 )^2}{75/4} = 1\]

  • \[\frac{(x + 1 )^2}{25/4} - \frac{(y + 4 )^2}{75/4} = 1\]

  • \[\frac{(x - 1 )^2}{75/4} - \frac{(y - 4 )^2}{25/4} = 1\]

  • none of these

Exercise 27.3 | Q 15 | Page 19

The length of the straight line x − 3y = 1 intercepted by the hyperbola x2 − 4y2 = 1 is 

  • \[\frac{6}{\sqrt{5}}\]

  • \[3\sqrt{\frac{2}{5}}\]

  • \[6\sqrt{\frac{2}{5}}\]

  •  none of these

Exercise 27.3 | Q 16 | Page 20

The latus-rectum of the hyperbola 16x2 − 9y2 = 144 is

  • 16/3

  •  32/3

  •  8/3

  •  4/3

Exercise 27.3 | Q 17 | Page 20

The foci of the hyperbola 2x2 − 3y2 = 5 are

  • \[( \pm 5/\sqrt{6}, 0)\]

  • (± 5/6, 0)

  • \[( \pm \sqrt{5}/6, 0)\]

  • none of these

Exercise 27.3 | Q 18 | Page 20

The eccentricity the hyperbola \[x = \frac{a}{2}\left( t + \frac{1}{t} \right), y = \frac{a}{2}\left( t - \frac{1}{t} \right)\] is

  • \[\sqrt{2}\]

  • \[\sqrt{3}\]

  • \[2\sqrt{3}\]

  • \[3\sqrt{2}\]

Exercise 27.3 | Q 19 | Page 20

The equation of the hyperbola whose centre is (6, 2) one focus is (4, 2) and of eccentricity 2 is

  • 3 (x − 6)2 − (y −2)2 = 3

  • (x − 6)2 − 3 (y − 2)2 = 1

  • (x − 6)2 − 2 (y −2)2 = 1

  • 2 (x − 6)2 − (y − 2)2 = 1

Exercise 27.3 | Q 20 | Page 20

The locus of the point of intersection of the lines \[\sqrt{3}x - y - 4\sqrt{3}\lambda = 0 \text { and } \sqrt{3}\lambda  + \lambda - 4\sqrt{3} = 0\]  is a hyperbola of eccentricity

  • 1

  • 2

  • 3

  • 4

Solutions for 27: Hyperbola

Exercise 27.1Exercise 27.2Exercise 27.3
RD Sharma solutions for Mathematics [English] Class 11 chapter 27 - Hyperbola - Shaalaa.com

RD Sharma solutions for Mathematics [English] Class 11 chapter 27 - Hyperbola

Shaalaa.com has the CBSE, Karnataka Board PUC Mathematics Mathematics [English] Class 11 CBSE, Karnataka Board PUC solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. RD Sharma solutions for Mathematics Mathematics [English] Class 11 CBSE, Karnataka Board PUC 27 (Hyperbola) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. RD Sharma textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics [English] Class 11 chapter 27 Hyperbola are Sections of a Cone, Introduction of Parabola, Standard Equations of Parabola, Latus Rectum, Introduction of Ellipse, Relationship Between Semi-major Axis, Semi-minor Axis and the Distance of the Focus from the Centre of the Ellipse, Special Cases of an Ellipse, Concept of Circle, Standard Equations of an Ellipse, Latus Rectum, Introduction of Hyperbola, Eccentricity, Standard Equation of Hyperbola, Latus Rectum, Standard Equation of a Circle, Eccentricity.

Using RD Sharma Mathematics [English] Class 11 solutions Hyperbola exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in RD Sharma Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board PUC Mathematics [English] Class 11 students prefer RD Sharma Textbook Solutions to score more in exams.

Get the free view of Chapter 27, Hyperbola Mathematics [English] Class 11 additional questions for Mathematics Mathematics [English] Class 11 CBSE, Karnataka Board PUC, and you can use Shaalaa.com to keep it handy for your exam preparation.

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