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Chapters
2: Relations
3: Functions
4: Measurement of Angles
5: Trigonometric Functions
6: Graphs of Trigonometric Functions
7: Values of Trigonometric function at sum or difference of angles
8: Transformation formulae
9: Values of Trigonometric function at multiples and submultiples of an angle
10: Sine and cosine formulae and their applications
11: Trigonometric equations
12: Mathematical Induction
13: Complex Numbers
14: Quadratic Equations
15: Linear Inequations
16: Permutations
17: Combinations
18: Binomial Theorem
19: Arithmetic Progression
20: Geometric Progression
21: Some special series
22: Brief review of cartesian system of rectangular co-ordinates
23: The straight lines
24: The circle
25: Parabola
26: Ellipse
▶ 27: Hyperbola
28: Introduction to three dimensional coordinate geometry
29: Limits
30: Derivatives
31: Mathematical reasoning
32: Statistics
33: Probability
![RD Sharma solutions for Mathematics [English] Class 11 chapter 27 - Hyperbola RD Sharma solutions for Mathematics [English] Class 11 chapter 27 - Hyperbola - Shaalaa.com](/images/9788193663004-mathematics-english-class-11_6:972cafaba17f4949992ada196fa0f041.jpg)
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Solutions for Chapter 27: Hyperbola
Below listed, you can find solutions for Chapter 27 of CBSE, Karnataka Board PUC RD Sharma for Mathematics [English] Class 11.
RD Sharma solutions for Mathematics [English] Class 11 27 Hyperbola Exercise 27.1 [Pages 13 - 14]
The equation of the directrix of a hyperbola is x − y + 3 = 0. Its focus is (−1, 1) and eccentricity 3. Find the equation of the hyperbola.
Find the equation of the hyperbola whose focus is (0, 3), directrix is x + y − 1 = 0 and eccentricity = 2 .
Find the equation of the hyperbola whose focus is (1, 1), directrix is 3x + 4y + 8 = 0 and eccentricity = 2 .
Find the equation of the hyperbola whose focus is (1, 1) directrix is 2x + y = 1 and eccentricity = \[\sqrt{3}\].
Find the equation of the hyperbola whose focus is (2, −1), directrix is 2x + 3y = 1 and eccentricity = 2 .
Find the equation of the hyperbola whose focus is (a, 0), directrix is 2x − y + a = 0 and eccentricity = \[\frac{4}{3}\].
Find the equation of the hyperbola whose focus is (2, 2), directrix is x + y = 9 and eccentricity = 2.
Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .
9x2 − 16y2 = 144
Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .
16x2 − 9y2 = −144
Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .
4x2 − 3y2 = 36
Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .
3x2 − y2 = 4
Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .
2x2 − 3y2 = 5.
Find the axes, eccentricity, latus-rectum and the coordinates of the foci of the hyperbola 25x2 − 36y2 = 225.
Find the centre, eccentricity, foci and directrice of the hyperbola .
16x2 − 9y2 + 32x + 36y − 164 = 0
Find the centre, eccentricity, foci and directrice of the hyperbola.
x2 − y2 + 4x = 0
Find the centre, eccentricity, foci and directrice of the hyperbola .
x2 − 3y2 − 2x = 8.
Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in the distance between the foci = 16 and eccentricity = \[\sqrt{2}\].
Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in the conjugate axis is 5 and the distance between foci = 13 .
Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in the conjugate axis is 7 and passes through the point (3, −2).
Find the equation of the hyperbola whose foci are (6, 4) and (−4, 4) and eccentricity is 2.
Find the equation of the hyperbola whose vertices are (−8, −1) and (16, −1) and focus is (17, −1).
Find the equation of the hyperbola whose foci are (4, 2) and (8, 2) and eccentricity is 2.
Find the equation of the hyperbola whose vertices are at (0 ± 7) and foci at \[\left( 0, \pm \frac{28}{3} \right)\] .
Find the equation of the hyperbola whose vertices are at (± 6, 0) and one of the directrices is x = 4.
Find the equation of the hyperbola whose foci at (± 2, 0) and eccentricity is 3/2.
Find the eccentricity of the hyperbola, the length of whose conjugate axis is \[\frac{3}{4}\] of the length of transverse axis.
Find the equation of the hyperboala whose focus is at (5, 2), vertex at (4, 2) and centre at (3, 2).
Find the equation of the hyperboala whose focus is at (4, 2), centre at (6, 2) and e = 2.
If P is any point on the hyperbola whose axis are equal, prove that SP. S'P = CP2.
Find the equation of the hyperbola satisfying the given condition :
vertices (± 2, 0), foci (± 3, 0)
Find the equation of the hyperbola satisfying the given condition :
vertices (0, ± 5), foci (0, ± 8)
Find the equation of the hyperbola satisfying the given condition :
vertices (0, ± 3), foci (0, ± 5)
Find the equation of the hyperbola satisfying the given condition :
foci (± \[3\sqrt{5}\] 0), the latus-rectum = 8
Find the equation of the hyperbola satisfying the given condition :
foci (0, ± 13), conjugate axis = 24
find the equation of the hyperbola satisfying the given condition:
foci (± \[3\sqrt{5}\] 0), the latus-rectum = 8
(vii) find the equation of the hyperbola satisfying the given condition:
foci (± 4, 0), the latus-rectum = 12
find the equation of the hyperbola satisfying the given condition:
vertices (± 7, 0), \[e = \frac{4}{3}\]
Find the equation of the hyperbola satisfying the given condition:
foci (0, ± \[\sqrt{10}\], passing through (2, 3).
find the equation of the hyperbola satisfying the given condition:
foci (0, ± 12), latus-rectum = 36
If the distance between the foci of a hyperbola is 16 and its ecentricity is \[\sqrt{2}\],then obtain its equation.
Show that the set of all points such that the difference of their distances from (4, 0) and (− 4,0) is always equal to 2 represents a hyperbola.
RD Sharma solutions for Mathematics [English] Class 11 27 Hyperbola Exercise 27.2 [Page 18]
Write the eccentricity of the hyperbola 9x2 − 16y2 = 144.
Write the eccentricity of the hyperbola whose latus-rectum is half of its transverse axis.
Write the coordinates of the foci of the hyperbola 9x2 − 16y2 = 144.
Write the equation of the hyperbola of eccentricity \[\sqrt{2}\], if it is known that the distance between its foci is 16.
If the foci of the ellipse \[\frac{x^2}{16} + \frac{y^2}{b^2} = 1\] and the hyperbola \[\frac{x^2}{144} - \frac{y^2}{81} = \frac{1}{25}\] coincide, write the value of b2.
Write the length of the latus-rectum of the hyperbola 16x2 − 9y2 = 144.
If the latus-rectum through one focus of a hyperbola subtends a right angle at the farther vertex, then write the eccentricity of the hyperbola.
Write the distance between the directrices of the hyperbola x = 8 sec θ, y = 8 tan θ.
Write the equation of the hyperbola whose vertices are (± 3, 0) and foci at (± 5, 0).
If e1 and e2 are respectively the eccentricities of the ellipse \[\frac{x^2}{18} + \frac{y^2}{4} = 1\]
and the hyperbola \[\frac{x^2}{9} - \frac{y^2}{4} = 1\] then write the value of 2 e12 + e22.
RD Sharma solutions for Mathematics [English] Class 11 27 Hyperbola Exercise 27.3 [Pages 18 - 20]
Equation of the hyperbola whose vertices are (± 3, 0) and foci at (± 5, 0), is
16x2 − 9y2 = 144
9x2 − 16y2 = 144
25x2 − 9y2 = 225
9x2 − 25y2 = 81
If e1 and e2 are respectively the eccentricities of the ellipse \[\frac{x^2}{18} + \frac{y^2}{4} = 1\] and the hyperbola \[\frac{x^2}{9} - \frac{y^2}{4} = 1\] , then the relation between e1 and e2 is
3 e12 + e22 = 2
e12 + 2 e22 = 3
2 e12 + e22 = 3
e12 + 3 e22 = 2
The distance between the directrices of the hyperbola x = 8 sec θ, y = 8 tan θ, is
\[8\sqrt{2}\]
\[16\sqrt{2}\]
\[4\sqrt{2}\]
\[6\sqrt{2}\]
The equation of the conic with focus at (1, −1) directrix along x − y + 1 = 0 and eccentricity \[\sqrt{2}\] is
xy = 1
2xy + 4x − 4y − 1= 0
x2 − y2 = 1
2xy − 4x + 4y + 1 = 0
The eccentricity of the conic 9x2 − 16y2 = 144 is
\[\frac{5}{4}\]
\[\frac{4}{3}\]
\[\frac{4}{5}\]
\[\sqrt{7}\]
A point moves in a plane so that its distances PA and PB from two fixed points A and B in the plane satisfy the relation PA − PB = k (k ≠ 0), then the locus of P is
a hyperbola
a branch of the hyperbola
a parabola
an ellipse
The eccentricity of the hyperbola whose latus-rectum is half of its transverse axis, is
\[\frac{1}{\sqrt{2}}\]
\[\sqrt{\frac{2}{3}}\]
\[\sqrt{\frac{3}{2}}\]
none of these.
The eccentricity of the hyperbola x2 − 4y2 = 1 is
\[\frac{\sqrt{3}}{2}\]
\[\frac{\sqrt{5}}{2}\]
\[\frac{2}{\sqrt{3}}\]
\[\frac{2}{\sqrt{5}}\]
The difference of the focal distances of any point on the hyperbola is equal to
length of the conjugate axis
eccentricity
length of the transverse axis
Latus-rectum
The foci of the hyperbola 9x2 − 16y2 = 144 are
(± 4, 0)
(0, ± 4)
(± 5, 0)
(0, ± 5)
The distance between the foci of a hyperbola is 16 and its eccentricity is \[\sqrt{2}\], then equation of the hyperbola is
x2 + y2 = 32
x2 − y2 = 16
x2 + y2 = 16
x2 − y2 = 32
If e1 is the eccentricity of the conic 9x2 + 4y2 = 36 and e2 is the eccentricity of the conic 9x2 − 4y2 = 36, then
e12 − e22 = 2
2 < e22 − e12 < 3
e22 − e12 = 2
e22 − e12 > 3
If the eccentricity of the hyperbola x2 − y2 sec2α = 5 is \[\sqrt{3}\] times the eccentricity of the ellipse x2 sec2 α + y2 = 25, then α =
\[\frac{\pi}{6}\]
\[\frac{\pi}{4}\]
\[\frac{\pi}{3}\]
\[\frac{\pi}{2}\]
The equation of the hyperbola whose foci are (6, 4) and (−4, 4) and eccentricity 2, is
\[\frac{(x - 1 )^2}{25/4} - \frac{(y - 4 )^2}{75/4} = 1\]
\[\frac{(x + 1 )^2}{25/4} - \frac{(y + 4 )^2}{75/4} = 1\]
\[\frac{(x - 1 )^2}{75/4} - \frac{(y - 4 )^2}{25/4} = 1\]
none of these
The length of the straight line x − 3y = 1 intercepted by the hyperbola x2 − 4y2 = 1 is
\[\frac{6}{\sqrt{5}}\]
\[3\sqrt{\frac{2}{5}}\]
\[6\sqrt{\frac{2}{5}}\]
none of these
The latus-rectum of the hyperbola 16x2 − 9y2 = 144 is
16/3
32/3
8/3
4/3
The foci of the hyperbola 2x2 − 3y2 = 5 are
\[( \pm 5/\sqrt{6}, 0)\]
(± 5/6, 0)
\[( \pm \sqrt{5}/6, 0)\]
none of these
The eccentricity the hyperbola \[x = \frac{a}{2}\left( t + \frac{1}{t} \right), y = \frac{a}{2}\left( t - \frac{1}{t} \right)\] is
\[\sqrt{2}\]
\[\sqrt{3}\]
\[2\sqrt{3}\]
\[3\sqrt{2}\]
The equation of the hyperbola whose centre is (6, 2) one focus is (4, 2) and of eccentricity 2 is
3 (x − 6)2 − (y −2)2 = 3
(x − 6)2 − 3 (y − 2)2 = 1
(x − 6)2 − 2 (y −2)2 = 1
2 (x − 6)2 − (y − 2)2 = 1
The locus of the point of intersection of the lines \[\sqrt{3}x - y - 4\sqrt{3}\lambda = 0 \text { and } \sqrt{3}\lambda + \lambda - 4\sqrt{3} = 0\] is a hyperbola of eccentricity
1
2
3
4
Solutions for 27: Hyperbola
![RD Sharma solutions for Mathematics [English] Class 11 chapter 27 - Hyperbola RD Sharma solutions for Mathematics [English] Class 11 chapter 27 - Hyperbola - Shaalaa.com](/images/9788193663004-mathematics-english-class-11_6:972cafaba17f4949992ada196fa0f041.jpg)
RD Sharma solutions for Mathematics [English] Class 11 chapter 27 - Hyperbola
Shaalaa.com has the CBSE, Karnataka Board PUC Mathematics Mathematics [English] Class 11 CBSE, Karnataka Board PUC solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. RD Sharma solutions for Mathematics Mathematics [English] Class 11 CBSE, Karnataka Board PUC 27 (Hyperbola) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Mathematics [English] Class 11 chapter 27 Hyperbola are Sections of a Cone, Introduction of Parabola, Standard Equations of Parabola, Latus Rectum, Introduction of Ellipse, Relationship Between Semi-major Axis, Semi-minor Axis and the Distance of the Focus from the Centre of the Ellipse, Special Cases of an Ellipse, Concept of Circle, Standard Equations of an Ellipse, Latus Rectum, Introduction of Hyperbola, Eccentricity, Standard Equation of Hyperbola, Latus Rectum, Standard Equation of a Circle, Eccentricity.
Using RD Sharma Mathematics [English] Class 11 solutions Hyperbola exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in RD Sharma Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board PUC Mathematics [English] Class 11 students prefer RD Sharma Textbook Solutions to score more in exams.
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