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प्रश्न
Evaluate the following limit :
`lim_(x -> 1) [(x + x^3 + x^5 + ... + x^(2"n" - 1) - "n")/(x - 1)]`
उत्तर
`lim_(x -> 1) [(x + x^3 + x^5 + ... + x^(2"n" - 1) - "n")/(x - 1)]`
= `lim_(x -> 1) [(x + x^3 + x^5 + ... + x^(2"n" - 1) - (1 + 1 + 1 + ... "n times"))/(x - 1)]`
= `lim_(x -> 1)[((x - 1) + (x^3 - 1) + (x^5 - 1) + ... + (x^(2"n" - 1) - 1) ... ("n brackets"))/(x - 1)]`
(∵ 1, 3, 5, …, 2n – 1 are the first n odd numbers)
= `lim_(x -> 1)[(x^1 - 1^1)/(x - 1) + (x^3 - 1^3)/(x - 1) + (x^5 - 1^5)/(x - 1) + ... + (x^(2"n" - 1) - 1^(2"n" - 1))/(x - 1)]`
= 1(1)0 + 3(1)2 + 5(1)4 + … + (2n – 1) (1)2n–2
= 1 + 3 + 5 + ... + (2n – 1)
= `sum_("r" = 1)^"n"(2"r" - 1)`
= `2 sum_("r" = 1)^"n" "r" - sum_("r" = 1)^"n" 1`
= `2*("n"("n" + 1))/2 - "n"`
= n(n + 1) – n
= n2 + n – n
= n2
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