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Find the Total Number of Ways in Which Six '+' and Four '−' Signs Can Be Arranged in a Line Such that No Two '−' Signs Occur Together. - Mathematics

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प्रश्न

Find the total number of ways in which six '+' and four '−' signs can be arranged in a line such that no two '−' signs occur together.

उत्तर

Six '+' signs can be arranged in a row in\[\frac{6!}{6!}\] = 1 way
Now, we are left with seven places in which four different things can be arranged in 7P4ways.
Since all the four '- ' signs are identical, four '- ' signs can be arranged in\[{{7}{}{P}_4}{4!}\]ways, i.e. 35 ways.
Number of ways = 1\[\times\]35 = 35

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Factorial N (N!) Permutations and Combinations
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अध्याय 16: Permutations - Exercise 16.5 [पृष्ठ ४३]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 16 Permutations
Exercise 16.5 | Q 26 | पृष्ठ ४३

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