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Solution of dddydx-y = 1, y(0) = 1 is given by ______. - Mathematics

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प्रश्न

Solution of `("d"y)/("d"x) - y` = 1, y(0) = 1 is given by ______.

विकल्प

  • xy = – ex

  • xy = – e-x 

  • xy = – 1

  • y = 2ex – 1

MCQ
रिक्त स्थान भरें

उत्तर

Solution of `("d"y)/("d"x) - y` = 1, y(0) = 1 is given by y = 2ex – 1.

Explanation:

The given differential equation is `("d"y)/("d"x) - y` = 1

Here, P = –1, Q = 1

∴ Integrating factor, I.F. = `"e"^(intPdx)`

= `"e"^(int -1"d"x)`

= `"e"^-x`

So, the solution is `y xx "I"."F". = int "Q" ."I"."F". "d"x + "c"`

⇒ `y xx "e"^-x = int 1."e"^-x  "d"x + "c"`

⇒ `y * "e"^-x = -"e"^-x + "c"`

Put x = 0, y = 1

⇒ `1. "e"^0 = - "e"^0 + "c"`

⇒ 1 = `-1 + "c"`

∴ c = 2

So the equation is `y * "e"^-x = -"e"^-x + 2`

⇒ y = `-1 + 2"e"^x`

= `2"e"^x - 1`.

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अध्याय 9: Differential Equations - Exercise [पृष्ठ १९६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 9 Differential Equations
Exercise | Q 44 | पृष्ठ १९६

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