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The area of the region bounded by the curve y = 16-x2 and x-axis is ______. - Mathematics

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प्रश्न

The area of the region bounded by the curve y = `sqrt(16 - x^2)` and x-axis is ______.

विकल्प

  • 8 sq.units

  • 20π sq.units

  • 16π sq.units

  • 256π sq.units

MCQ
रिक्त स्थान भरें

उत्तर

The area of the region bounded by the curve y = `sqrt(16 - x^2)` and x-axis is 8 sq.units.

Explanation:


Here, equation of curve is y = `sqrt(16 - x^2)`

Required area = `2[int_0^4 sqrt(16 - x^2)  "d"x]`

= `2[x/2 sqrt(16 - x^2) + 16/2 sin^-1  x/4]_0^4`

= `2[(0 + 8 sin^-1 4/4) - (0 + 0)]`

= `2[8sin^-1 (1)]`

= `16 * pi/2`

= 8 sq.units.

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अध्याय 8: Application Of Integrals - Exercise [पृष्ठ १७७]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 8 Application Of Integrals
Exercise | Q 26 | पृष्ठ १७७

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