Advertisements
Advertisements
प्रश्न
Choose the correct alternative from the following.
`int (1 - "x")^(-2) "dx"` =
पर्याय
`(1 + "x")^-1` + c
`(1 - "x")^-1` + c
`(1 - "x")^-1 - 1` + c
`(1 - "x")^-1 + 1` + c
उत्तर
`(1 - "x")^-1` + c
Explanation:
`int (1 - "x")^(-2) "dx" = (1 - "x")^-1/(- 1 xx -1)` + c
`= (1 - "x")^-1` + c
APPEARS IN
संबंधित प्रश्न
`int1/xlogxdx=...............`
(A)log(log x)+ c
(B) 1/2 (logx )2+c
(C) 2log x + c
(D) log x + c
Integrate the function in x sin 3x.
Integrate the function in `x^2e^x`.
Integrate the function in x sin-1 x.
Integrate the function in x (log x)2.
Integrate the function in `e^x (1/x - 1/x^2)`.
Evaluate the following : `int x.sin^2x.dx`
Evaluate the following : `int e^(2x).cos 3x.dx`
Evaluate the following: `int x.sin^-1 x.dx`
Evaluate the following : `int(sin(logx)^2)/x.log.x.dx`
Evaluate the following : `int logx/x.dx`
Integrate the following functions w.r.t. x : `e^(2x).sin3x`
Choose the correct options from the given alternatives :
`int (1)/(x + x^5)*dx` = f(x) + c, then `int x^4/(x + x^5)*dx` =
Integrate the following w.r.t.x : `(1)/(xsin^2(logx)`
Integrate the following w.r.t.x : `log (1 + cosx) - xtan(x/2)`
Integrate the following w.r.t.x : e2x sin x cos x
Evaluate: `int "dx"/("9x"^2 - 25)`
`int(x + 1/x)^3 dx` = ______.
`int 1/sqrt(x^2 - a^2)dx` = ______.
Evaluate the following.
`intx^3/sqrt(1+x^4)`dx
