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Find the Slope of the Tangent and the Normal to the Following Curve at the Indicted Point Xy = 6 at (1, 6) ? - Mathematics

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प्रश्न

Find the slope of the tangent and the normal to the following curve at the indicted point  xy = 6 at (1, 6) ?

बेरीज

उत्तर

\[ xy = 6\]

\[\text { On differentiating both sides w.r.t. x, we get }\]

\[x\frac{dy}{dx} + y = 0\]

\[ \Rightarrow x\frac{dy}{dx} = - y\]

\[ \Rightarrow \frac{dy}{dx} = \frac{- y}{x}\]

\[\text { Now,} \]

\[\text { Slope of the tangent }= \left( \frac{dy}{dx} \right)_\left( 1, 6 \right) =\frac{- y}{x}=\frac{- 6}{1}=-6\]

\[\text{ Slope of the normal }=\frac{- 1}{\left( \frac{dy}{dx} \right)_\left( 1, 6 \right)}=\frac{- 1}{- 6}=\frac{1}{6}\]

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पाठ 16: Tangents and Normals - Exercise 16.1 [पृष्ठ १०]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 16 Tangents and Normals
Exercise 16.1 | Q 1.1 | पृष्ठ १०

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