मराठी

If a, b, c, d are four distinct positive quantities in G.P., then show that a + d > b + c - Mathematics

Advertisements
Advertisements

प्रश्न

If a, b, c, d are four distinct positive quantities in G.P., then show that a + d > b + c

बेरीज

उत्तर

Since a, b, c, d are in G.P.

Again A.M. > G.M. for the first three terms

`(a + c)/2 > b`   .....`("Since"  sqrt(ac) = b)`

⇒ a + c > 2b   ....(3)

Similarly, for the last three terms

`(b + d)/2 > c`  .....`("Since"  sqrt(bd) = c)`

⇒ b + d > 2c  ....(4)

Adding (3) and (4), we get

(a + c) + (b + d) > 2b + 2c

a + d > b + c

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Sequences and Series - Solved Examples [पृष्ठ १५५]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
पाठ 9 Sequences and Series
Solved Examples | Q 11.(ii) | पृष्ठ १५५

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the 12th term of a G.P. whose 8th term is 192 and the common ratio is 2.


The sum of first three terms of a G.P. is 16 and the sum of the next three terms is 128. Determine the first term, the common ratio and the sum to n terms of the G.P.


If the 4th, 10th and 16th terms of a G.P. are x, y and z, respectively. Prove that x, y, z are in G.P.


Show that one of the following progression is a G.P. Also, find the common ratio in case:

4, −2, 1, −1/2, ...


Find :

the 8th term of the G.P. 0.3, 0.06, 0.012, ...


If the G.P.'s 5, 10, 20, ... and 1280, 640, 320, ... have their nth terms equal, find the value of n.


Find three numbers in G.P. whose sum is 65 and whose product is 3375.


Find three numbers in G.P. whose product is 729 and the sum of their products in pairs is 819.


Find the sum of the following geometric series:

`3/5 + 4/5^2 + 3/5^3 + 4/5^4 + ....` to 2n terms;


Find the sum of the following geometric series:

\[\frac{a}{1 + i} + \frac{a}{(1 + i )^2} + \frac{a}{(1 + i )^3} + . . . + \frac{a}{(1 + i )^n} .\]


Find the sum of the following series:

9 + 99 + 999 + ... to n terms;


Show that the ratio of the sum of first n terms of a G.P. to the sum of terms from (n + 1)th to (2n)th term is \[\frac{1}{r^n}\].


Let an be the nth term of the G.P. of positive numbers.

Let \[\sum^{100}_{n = 1} a_{2n} = \alpha \text { and } \sum^{100}_{n = 1} a_{2n - 1} = \beta,\] such that α ≠ β. Prove that the common ratio of the G.P. is α/β.


If a, b, c, d are in G.P., prove that:

 (a + b + c + d)2 = (a + b)2 + 2 (b + c)2 + (c + d)2


Insert 6 geometric means between 27 and  \[\frac{1}{81}\] .


The sum of an infinite G.P. is 4 and the sum of the cubes of its terms is 92. The common ratio of the original G.P. is 


If abc are in G.P. and xy are AM's between ab and b,c respectively, then 


Given that x > 0, the sum \[\sum^\infty_{n = 1} \left( \frac{x}{x + 1} \right)^{n - 1}\] equals 


In a G.P. of even number of terms, the sum of all terms is five times the sum of the odd terms. The common ratio of the G.P. is 


Let x be the A.M. and yz be two G.M.s between two positive numbers. Then, \[\frac{y^3 + z^3}{xyz}\]  is equal to 


The product (32), (32)1/6 (32)1/36 ... to ∞ is equal to 


For a G.P. If t4 = 16, t9 = 512, find S10


The value of a house appreciates 5% per year. How much is the house worth after 6 years if its current worth is ₹ 15 Lac. [Given: (1.05)5 = 1.28, (1.05)6 = 1.34]


Select the correct answer from the given alternative.

The sum of 3 terms of a G.P. is `21/4` and their product is 1 then the common ratio is –


Select the correct answer from the given alternative.

Which of the following is not true, where A, G, H are the AM, GM, HM of a and b respectively. (a, b > 0)


Answer the following:

In a G.P., the fourth term is 48 and the eighth term is 768. Find the tenth term


Answer the following:

If pth, qth and rth terms of a G.P. are x, y, z respectively. Find the value of xq–r .yr–p .zp–q


If pth, qth, and rth terms of an A.P. and G.P. are both a, b and c respectively, show that ab–c . bc – a . ca – b = 1


Find a G.P. for which sum of the first two terms is – 4 and the fifth term is 4 times the third term.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×