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Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 12 - Mid-point and Its Converse [ Including Intercept Theorem] [Latest edition]

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Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 12 - Mid-point and Its Converse [ Including Intercept Theorem] - Shaalaa.com
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Solutions for Chapter 12: Mid-point and Its Converse [ Including Intercept Theorem]

Below listed, you can find solutions for Chapter 12 of CISCE Selina for Concise Mathematics [English] Class 9 ICSE.


Exercise 12 (A)Exercise 12 (B)
Exercise 12 (A) [Pages 150 - 151]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 12 Mid-point and Its Converse [ Including Intercept Theorem] Exercise 12 (A) [Pages 150 - 151]

Exercise 12 (A) | Q 1 | Page 150

In triangle ABC, M is mid-point of AB and a straight line through M and parallel to BC cuts AC in N. Find the lengths of AN and MN if Bc = 7 cm and Ac = 5 cm.

Exercise 12 (A) | Q 2 | Page 150

Prove that the figure obtained by joining the mid-points of the adjacent sides of a rectangle is a rhombus.

Exercise 12 (A) | Q 3 | Page 150

D, E, and F are the mid-points of the sides AB, BC and CA of an isosceles ΔABC in which AB = BC.

Prove that ΔDEF is also isosceles.

Exercise 12 (A) | Q 4 | Page 150

The following figure shows a trapezium ABCD in which AB // DC. P is the mid-point of AD and PR // AB. Prove that:

PR = `[1]/[2]` ( AB + CD)

Exercise 12 (A) | Q 5 | Page 150

The figure, given below, shows a trapezium ABCD. M and N are the mid-point of the non-parallel sides AD and BC respectively. Find: 

  1. MN, if AB = 11 cm and DC = 8 cm.
  2. AB, if DC = 20 cm and MN = 27 cm.
  3. DC, if MN = 15 cm and AB = 23 cm.
Exercise 12 (A) | Q 6 | Page 150

The diagonals of a quadrilateral intersect at right angles. Prove that the figure obtained by joining the mid-points of the adjacent sides of the quadrilateral is rectangle.

Exercise 12 (A) | Q 7 | Page 150

L and M are the mid-point of sides AB and DC respectively of parallelogram ABCD. Prove that segments DL and BM trisect diagonal AC.

Exercise 12 (A) | Q 8 | Page 150

ABCD is a quadrilateral in which AD = BC. E, F, G and H are the mid-points of AB, BD, CD and Ac respectively. Prove that EFGH is a rhombus.

Exercise 12 (A) | Q 9 | Page 150

A parallelogram ABCD has P the mid-point of Dc and Q a point of Ac such that

CQ = `[1]/[4]`AC. PQ produced meets BC at R.

Prove that
(i)R is the midpoint of BC
(ii) PR = `[1]/[2]` DB

Exercise 12 (A) | Q 10 | Page 150

D, E, and F are the mid-points of the sides AB, BC, and CA respectively of ΔABC. AE meets DF at O. P and Q are the mid-points of OB and OC respectively. Prove that DPQF is a parallelogram.

Exercise 12 (A) | Q 11 | Page 151

In triangle ABC, P is the mid-point of side BC. A line through P and parallel to CA meets AB at point Q, and a line through Q and parallel to BC meets median AP at point R.
Prove that : (i) AP = 2AR
                   (ii) BC = 4QR

Exercise 12 (A) | Q 12 | Page 151

In trapezium ABCD, AB is parallel to DC; P and Q are the mid-points of AD and BC respectively. BP produced meets CD produced at point E.

Prove that:

  1. Point P bisects BE,
  2. PQ is parallel to AB.
Exercise 12 (A) | Q 13 | Page 151

In a triangle ABC, AD is a median and E is mid-point of median AD. A line through B and E meets AC at point F.

Prove that: AC = 3AF.

Exercise 12 (A) | Q 14 | Page 151

D and F are midpoints of sides AB and AC of a triangle ABC. A line through F and parallel to AB meets BC at point E.

  1. Prove that BDFE is a parallelogram
  2.  Find AB, if EF = 4.8 cm.
Exercise 12 (A) | Q 15 | Page 151

In triangle ABC, AD is the median and DE, drawn parallel to side BA, meets AC at point E.
Show that BE is also a median.

Exercise 12 (A) | Q 16 | Page 151

In ∆ABC, E is the mid-point of the median AD, and BE produced meets side AC at point Q.

Show that BE: EQ = 3: 1.

Exercise 12 (A) | Q 17 | Page 151

In the given figure, M is mid-point of AB and DE, whereas N is mid-point of BC and DF.
Show that: EF = AC.

Exercise 12 (B) [Pages 153 - 154]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 12 Mid-point and Its Converse [ Including Intercept Theorem] Exercise 12 (B) [Pages 153 - 154]

Exercise 12 (B) | Q 1 | Page 153

Use the following figure to find:
(i) BC, if AB = 7.2 cm.
(ii) GE, if FE = 4 cm.
(iii) AE, if BD = 4.1 cm
(iv) DF, if CG = 11 cm.

Exercise 12 (B) | Q 2 | Page 153

In the figure, give below, 2AD = AB, P is mid-point of AB, Q is mid-point of DR and PR // BS. Prove that:
(i) AQ // BS
(ii) DS = 3 Rs.

Exercise 12 (B) | Q 3 | Page 153

The side AC of a triangle ABC is produced to point E so that CE = AC. D is the mid-point of BC and ED produced meets AB at F. Lines through D and C are drawn parallel to AB which meet AC at point P and EF at point R respectively.

Prove that:

  1. 3DF = EF
  2. 4CR = AB
Exercise 12 (B) | Q 4 | Page 154

In triangle ABC, the medians BP and CQ are produced up to points M and N respectively such that BP = PM and CQ = QN. Prove that:

  1. M, A, and N are collinear.
  2. A is the mid-point of MN.
Exercise 12 (B) | Q 5 | Page 154

In triangle ABC, angle B is obtuse. D and E are mid-points of sides AB and BC respectively and F is a point on side AC such that EF is parallel to AB. Show that BEFD is a parallelogram.

Exercise 12 (B) | Q 6 | Page 154

In parallelogram ABCD, E and F are mid-points of the sides AB and CD respectively. The line segments AF and BF meet the line segments ED and EC at points G and H respectively.
Prove that:
(i) Triangles HEB and FHC are congruent;
(ii) GEHF is a parallelogram.

Exercise 12 (B) | Q 7 | Page 154

In triangle ABC, D and E are points on side AB such that AD = DE = EB. Through D and E, lines are drawn parallel to BC which meet side AC at points F and G respectively. Through F and G, lines are drawn parallel to AB which meets side BC at points M and N respectively. Prove that: BM = MN = NC.

Exercise 12 (B) | Q 8 | Page 154

In triangle ABC; M is mid-point of AB, N is mid-point of AC and D is any point in base BC. Use the intercept Theorem to show that MN bisects AD.

Exercise 12 (B) | Q 9 | Page 154

If the quadrilateral formed by joining the mid-points of the adjacent sides of quadrilateral ABCD is a rectangle,
show that the diagonals AC and BD intersect at the right angle.

Exercise 12 (B) | Q 10 | Page 154

In triangle ABC ; D and E are mid-points of the sides AB and AC respectively. Through E, a straight line is drawn parallel to AB to meet BC at F.
Prove that BDEF is a parallelogram. If AB = 16 cm, AC = 12 cm and BC = 18 cm,
find the perimeter of the parallelogram BDEF.

Exercise 12 (B) | Q 11 | Page 154

In the given figure, AD and CE are medians and DF // CE.
Prove that: FB = `1/4` AB.

Exercise 12 (B) | Q 12 | Page 154

In parallelogram ABCD, E is the mid-point of AB and AP is parallel to EC which meets DC at point O and BC produced at P.
Prove that:
(i) BP = 2AD
(ii) O is the mid-point of AP.

Exercise 12 (B) | Q 13 | Page 154

In trapezium ABCD, sides AB and DC are parallel to each other. E is mid-point of AD and F is mid-point of BC.
Prove that: AB + DC = 2EF.

Exercise 12 (B) | Q 14 | Page 154

In Δ ABC, AD is the median and DE is parallel to BA, where E is a point in AC. Prove that BE is also a median.

Exercise 12 (B) | Q 15 | Page 154

Adjacent sides of a parallelogram are equal and one of the diagonals is equal to any one of the sides of this parallelogram. Show that its diagonals are in ratio √3:1.

Solutions for 12: Mid-point and Its Converse [ Including Intercept Theorem]

Exercise 12 (A)Exercise 12 (B)
Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 12 - Mid-point and Its Converse [ Including Intercept Theorem] - Shaalaa.com

Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 12 - Mid-point and Its Converse [ Including Intercept Theorem]

Shaalaa.com has the CISCE Mathematics Concise Mathematics [English] Class 9 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Selina solutions for Mathematics Concise Mathematics [English] Class 9 ICSE CISCE 12 (Mid-point and Its Converse [ Including Intercept Theorem]) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Selina textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Concise Mathematics [English] Class 9 ICSE chapter 12 Mid-point and Its Converse [ Including Intercept Theorem] are Theorem of Midpoints of Two Sides of a Triangle, Equal Intercept Theorem.

Using Selina Concise Mathematics [English] Class 9 ICSE solutions Mid-point and Its Converse [ Including Intercept Theorem] exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Selina Solutions are essential questions that can be asked in the final exam. Maximum CISCE Concise Mathematics [English] Class 9 ICSE students prefer Selina Textbook Solutions to score more in exams.

Get the free view of Chapter 12, Mid-point and Its Converse [ Including Intercept Theorem] Concise Mathematics [English] Class 9 ICSE additional questions for Mathematics Concise Mathematics [English] Class 9 ICSE CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.

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