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Question
Evaluate: `int (2y^2)/(y^2 + 4)dx`
Solution
`I = int (2y^2)/(y^2 + 4) dy`
`= int(2y^2 + 8 - 8)/(y^2 + 4) dy`
`= 2int (y^2 + 4)/(y^2 + 4) dy - 8 int dy/(y^2 + 2^2)`
`= 2y - 4tan^(-1) (y/2) + c`
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