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Question
Factorise the following:
9x2 + 4y2 + 16z2 + 12xy – 16yz – 24xz
Solution
9x2 + 4y2 + 16z2 + 12xy – 16yz – 24xz
= (3x)2 + (2y)2 + (–4z)2 + 2(3x)(2y) + 2(2y)(–4z) + 2(–4z)(3x) ...[Using identity, (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca]
= (3x + 2y – 4z)2
= (3x + 2y – 4z)(3x + 2y – 4z)
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