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Integrate the function 17-6x-x2 - Mathematics

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Question

Integrate the function `1/sqrt(7 - 6x - x^2)`

Sum

Solution

Let `I = int 1/sqrt(7 - 6x - x^2)  dx`

`= dx/sqrt(7 - (x^2 + 6x))`

`= int dx/sqrt(7 - (x^2 + 6x + 9) + 9)`

`= int dx/sqrt(16 - (x + 3)^2)`

`= int dx/sqrt(4^2 - (x + 3)^2)`

`= sin^-1 ((x + 3)/4) + C`      `...[because 1/sqrt(a^2 - x^2)  dx = sin^-1  x/a + C]`

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Chapter 7: Integrals - Exercise 7.4 [Page 316]

APPEARS IN

NCERT Mathematics [English] Class 12
Chapter 7 Integrals
Exercise 7.4 | Q 12 | Page 316
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