हिंदी

Choose the Correct Answers The Value of `Int_0^1 Tan^(-1) (2x -1)/(1+X - X^2)` Dx is - Mathematics

Advertisements
Advertisements

प्रश्न

Choose the correct answers The value of `int_0^1 tan^(-1)  (2x -1)/(1+x - x^2)` dx is 

(A) 1

(B) 0

(C) –1

(D) `pi/4`

उत्तर

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Integrals - Exercise 7.12 [पृष्ठ ३५४]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 12
अध्याय 7 Integrals
Exercise 7.12 | Q 44 | पृष्ठ ३५४

वीडियो ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्न

Evaluate the following definite integrals as limit of sums.

`int_0^5 (x+1) dx`


Evaluate the following definite integrals as limit of sums.

`int_1^4 (x^2 - x) dx`


Evaluate the following definite integrals as limit of sums `int_(-1)^1 e^x dx`


Evaluate the following definite integrals as limit of sums.

`int_0^4 (x + e^(2x)) dx`


Evaluate the definite integral:

`int_0^(pi/4) (sinx cos x)/(cos^4 x + sin^4 x)`dx


Evaluate the definite integral:

`int_0^(pi/2) sin 2x tan^(-1) (sinx) dx`


Prove the following:

`int_(-1)^1 x^17 cos^4 xdx = 0`


Prove the following:

`int_0^(pi/4) 2 tan^3 xdx = 1 - log 2`


if `int_0^k 1/(2+ 8x^2) dx = pi/16` then the value of k is ________.

(A) `1/2`

(B) `1/3`

(C) `1/4`

(D) `1/5`


\[\int\frac{1}{\sqrt{\tan^{- 1} x} . \left( 1 + x^2 \right)} dx\]

\[\int\frac{4x + 3}{\sqrt{2 x^2 + 3x + 1}} dx\]

\[\int\frac{1 + \cos x}{\left( x + \sin x \right)^3} dx\]

\[\int\frac{\sin x}{\left( 1 + \cos x \right)^2} dx\]

 


\[\int\cot x \cdot \log \text{sin x dx}\]

\[\int\sec x \cdot \text{log} \left( \sec x + \tan x \right) dx\]

\[\text{ ∫  cosec x  log}      \left( \text{cosec x} - \cot x \right) dx\]

\[\int x^3 \sin \left( x^4 + 1 \right) dx\]

\[\int \sec^4    \text{ x   tan x dx} \]

\[\int\frac{1}{x\sqrt{x^4 - 1}} dx\]

\[\int\limits_0^1 \left( x e^x + \cos\frac{\pi x}{4} \right) dx\]

 


\[\int\limits_0^\pi \frac{\sin x}{\sin x + \cos x} dx\]

Evaluate the following integral:

\[\int\limits_{- 1}^1 \left| 2x + 1 \right| dx\]

\[\int\limits_{- \pi/2}^{\pi/2} \sin^4 x\ dx\]

Evaluate the following integrals as limit of sums:

\[\int_1^3 \left( 3 x^2 + 1 \right)dx\]

\[\int\frac{\sqrt{\tan x}}{\sin x \cos x} dx\]


Evaluate `int_1^4 ( 1+ x +e^(2x)) dx` as limit of sums.


Solve: (x2 – yx2) dy + (y2 + xy2) dx = 0 


Evaluate `int_(-1)^2 (7x - 5)"d"x` as a limit of sums


Evaluate the following as limit of sum:

`int_0^2 "e"^x "d"x`


Evaluate the following:

`int_0^1 (x"d"x)/sqrt(1 + x^2)`


Evaluate the following:

`int_0^pi x sin x cos^2x "d"x`


Evaluate the following:

`int_(pi/3)^(pi/2) sqrt(1 + cosx)/(1 - cos x)^(5/2)  "d"x`


The value of `int_(-pi)^pi sin^3x cos^2x  "d"x` is ______.


If f" = C, C ≠ 0, where C is a constant, then the value of `lim_(x -> 0) (f(x) - 2f (2x) + 3f (3x))/x^2` is


What is the derivative of `f(x) = |x|` at `x` = 0?


`lim_(x -> 0) (xroot(3)(z^2 - (z - x)^2))/(root(3)(8xz - 4x^2) + root(3)(8xz))^4` is equal to


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×