हिंदी

Find the Area of Ellipse `X^2/1 + Y^2/4 = 1` - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Find the area of ellipse `x^2/1 + y^2/4 = 1`

 

उत्तर

Required area = 4 Area (OAPB)

`= int_0^1 ydx`

`:. x^2/1 + y^2/4 = 1`

`:. y =- 2sqrt(1-x^2)`

∴Required area = `4int_0^1 2sqrt(1-x^2)dx`

`= 8[x/2 sqrt(1-x^2) + 1/2 sin^(-1)(x/1)]_0^1`

`= 8[{0+1/2 sin^1 (1)} - 0]`

`= 8 xx 1/2.pi/2 = 2pi
 sq.units"`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2017-2018 (March)

APPEARS IN

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Using integration, find the area bounded by the curve x2 = 4y and the line x = 4y − 2.


triangle bounded by the lines y = 0, y = x and x = 4 is revolved about the X-axis. Find the volume of the solid of revolution.


Find the area of the sector of a circle bounded by the circle x2 + y2 = 16 and the line y = x in the ftrst quadrant.


Using the method of integration, find the area of the triangular region whose vertices are (2, -2), (4, 3) and (1, 2).


Sketch the graph of y = |x + 4|. Using integration, find the area of the region bounded by the curve y = |x + 4| and x = –6 and x = 0.


Using definite integrals, find the area of the circle x2 + y2 = a2.


Using integration, find the area of the region bounded by the following curves, after making a rough sketch: y = 1 + | x + 1 |, x = −2, x = 3, y = 0.


Sketch the graph y = | x − 5 |. Evaluate \[\int\limits_0^1 \left| x - 5 \right| dx\]. What does this value of the integral represent on the graph.


Draw a rough sketch of the curve y = \[\frac{\pi}{2} + 2 \sin^2 x\] and find the area between x-axis, the curve and the ordinates x = 0, x = π.


Find the area of the region bounded by x2 = 16y, y = 1, y = 4 and the y-axis in the first quadrant.

 

Find the area of the region bounded by y =\[\sqrt{x}\] and y = x.


Using integration, find the area of the triangular region, the equations of whose sides are y = 2x + 1, y = 3x+ 1 and x = 4.


Find the area of the region included between the parabola y2 = x and the line x + y = 2.


Find the area of the region bounded by \[y = \sqrt{x}, x = 2y + 3\]  in the first quadrant and x-axis.


Find the area common to the circle x2 + y2 = 16 a2 and the parabola y2 = 6 ax.
                                   OR
Find the area of the region {(x, y) : y2 ≤ 6ax} and {(x, y) : x2 + y2 ≤ 16a2}.


Find the area enclosed by the parabolas y = 5x2 and y = 2x2 + 9.


Find the area of the region bounded by the parabola y2 = 2x + 1 and the line x − y − 1 = 0.


Find the area enclosed by the curve \[y = - x^2\] and the straight line x + y + 2 = 0. 


Make a sketch of the region {(x, y) : 0 ≤ y ≤ x2 + 3; 0 ≤ y ≤ 2x + 3; 0 ≤ x ≤ 3} and find its area using integration.


Find the area of the region enclosed between the two curves x2 + y2 = 9 and (x − 3)2 + y2 = 9.


Using integration, find the area of the following region: \[\left\{ \left( x, y \right) : \frac{x^2}{9} + \frac{y^2}{4} \leq 1 \leq \frac{x}{3} + \frac{y}{2} \right\}\]


Find the area of the region bounded by the parabola y2 = 2x and the straight line x − y = 4.


The area included between the parabolas y2 = 4x and x2 = 4y is (in square units)


The area bounded by the parabola y2 = 4ax and x2 = 4ay is ___________ .


The area bounded by the curve y = 4x − x2 and the x-axis is __________ .


Smaller area enclosed by the circle x2 + y2 = 4 and the line x + y = 2 is


Find the coordinates of a point of the parabola y = x2 + 7x + 2 which is closest to the straight line y = 3x − 3.


Find the area of the region bounded by the curve ay2 = x3, the y-axis and the lines y = a and y = 2a.


The area enclosed by the circle x2 + y2 = 2 is equal to ______.


Find the area of the region bounded by the parabola y2 = 2px, x2 = 2py


Using integration, find the area of the region bounded by the line 2y = 5x + 7, x- axis and the lines x = 2 and x = 8.


Compute the area bounded by the lines x + 2y = 2, y – x = 1 and 2x + y = 7.


Area of the region bounded by the curve y = cosx between x = 0 and x = π is ______.


Let f(x) be a continuous function such that the area bounded by the curve y = f(x), x-axis and the lines x = 0 and x = a is `a^2/2 + a/2 sin a + pi/2 cos a`, then `f(pi/2)` =


Find the area of the region bounded by the ellipse `x^2/4 + y^2/9` = 1.


The area of the region S = {(x, y): 3x2 ≤ 4y ≤ 6x + 24} is ______.


Find the area of the following region using integration ((x, y) : y2 ≤ 2x and y ≥ x – 4).


Sketch the region enclosed bounded by the curve, y = x |x| and the ordinates x = −1 and x = 1.


Hence find the area bounded by the curve, y = x |x| and the coordinates x = −1 and x = 1.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×