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Find the Sum of All Those Integers Between 100 and 800 Each of Which on Division by 16 Leaves the Remainder 7. - Mathematics

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प्रश्न

Find the sum of all those integers between 100 and 800 each of which on division by 16 leaves the remainder 7.

उत्तर

The sum of all those integers between 100 and 800 each of which on division by 16 leaves the remainder 7 are:
103, 119...791
Here, we have:
a = 103
d = 16

\[a_n = 791\]

\[\text { We know }: \]

\[ a_n = a + (n - 1)d\]

\[ \Rightarrow 791 = 103 + (n - 1) \times 16\]

\[ \Rightarrow 688 = 16n - 16\]

\[ \Rightarrow 704 = 16n\]

\[ \Rightarrow 44 = n\]

\[\text { Also }, S_n = \frac{n}{2}[2a + (n - 1)d]\]

\[ \Rightarrow S_{44} = \frac{44}{2}[2 \times 103 + (44 - 1) \times 16]\]

\[ \Rightarrow S_{44} = 22 [206 + 688]\]

\[ \Rightarrow S_{44} = 22 \times 894 = 19668\]

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अध्याय 19: Arithmetic Progression - Exercise 19.4 [पृष्ठ ३१]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 19 Arithmetic Progression
Exercise 19.4 | Q 13 | पृष्ठ ३१

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