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प्रश्न
If `sin theta = 1/2 , " write the value of" ( 3 cot^2 theta + 3).`
उत्तर
As , `sin theta = 1/2 `
So , `cosec theta = 1/ sin theta = 2 ........(i)`
Now ,
`3 cot ^2 theta + 3 `
= `3 ( cot^2 theta + 1)`
=`3 cosec^2 theta`
=` 3(2)^2 [ Using (i)]`
=3(4)
=12
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