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If `sec theta + tan theta = x," find the value of " sec theta`
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We have ,
`sec theta + tan theta = x ............(i)`
⇒ `(sec theta + tan theta )/1 xx (sec theta- tan theta )/(sec theta - tan theta ) = x`
`⇒ (sec ^2 theta - tan^2 theta )/( sec theta - tan theta) = x`
`⇒1/ (sec theta - tan theta ) = x/1`
`⇒ sec theta - tan theta = 1/x ` ............(ii)
ЁЭР┤ЁЭССЁЭССЁЭСЦЁЭСЫЁЭСФ (ЁЭСЦ)ЁЭСОЁЭСЫЁЭСС (ЁЭСЦЁЭСЦ), ЁЭСдЁЭСТ ЁЭСФЁЭСТЁЭСб
`2 sec theta = x+ 1/x`
⇒` 2 sec theta = (x^2+1)/x`
∴ `sec theta = (x^2 +1)/(2x)`
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