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If y=eacos-1x, -1 <= x <= 1 show that (1-x2)d2ydx2-xdydx-a2y=0 - Mathematics

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प्रश्न

If `y = e^(acos^(-1)x)`, -1 <= x <= 1 show that `(1- x^2) (d^2y)/(dx^2) -x dy/dx - a^2y = 0`

योग

उत्तर

y = `e^(a cos^(-1)x)`

On differentiating with respect to x,

`dy/dx = e^(a cos^(-1)x) d/dx a cos^-1 x`

`= e^(a cos^(-1)x) (- a)/sqrt(1 - x^2) = (- ay)/(sqrt(1 - x^2))`

On multiplying by `sqrt(1 - x^2)`,

`=> sqrt(1 - x^2) dy/dx` = - ay

On squaring,

`(dy/dx)^2 (1 - x^2) = a^2y^2`

Differentiating again with respect to x,

`=> 2 (dy/dx) (d^2y)/dx^2 (1 - x^2) + (dy/dx)^2  (- 2x) = 2a^2 y dy/dx`

Dividing by `2 dy/dx`,

`(d^2y)/dx^2 (1 - x^2) - x dy/dx = a^2 y`

Hence, `(1 - x^2) (d^2y)/dx^2 - x(dy/dx) - a^2 y = 0`

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अध्याय 5: Continuity and Differentiability - Exercise 5.9 [पृष्ठ १९२]

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एनसीईआरटी Mathematics [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.9 | Q 23 | पृष्ठ १९२

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