मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Choose the correct alternative: cos θ. sec θ = ? - Geometry Mathematics 2

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प्रश्न

Choose the correct alternative:

cos θ. sec θ = ?

पर्याय

  • 1

  • 0

  • `1/2`

  • `sqrt(2)`

MCQ

उत्तर

1

cos θ. sec θ = cos θ. `1/"cos θ"` = 1.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Trigonometry - Q.1 (A)

संबंधित प्रश्‍न

Prove the following trigonometric identities.

`(1 - sin theta)/(1 + sin theta) = (sec theta - tan theta)^2`


Prove the following trigonometric identities.

`(1 + cos A)/sin^2 A = 1/(1 - cos A)`


Prove the following trigonometric identities.

`(1 + tan^2 A) + (1 + 1/tan^2 A) = 1/(sin^2 A - sin^4 A)`


Prove the following trigonometric identities.

`(cot A - cos A)/(cot A + cos A) = (cosec A - 1)/(cosec A + 1)`


Prove the following identities:

`((1 + tan^2A)cotA)/(cosec^2A) = tan A`


Prove the following identities:

`(secA - tanA)/(secA + tanA) = 1 - 2secAtanA + 2tan^2A`


Prove the following identities:

`sqrt((1 - cosA)/(1 + cosA)) = sinA/(1 + cosA)`


Prove that:

`(cos^3A + sin^3A)/(cosA + sinA) + (cos^3A - sin^3A)/(cosA - sinA) = 2`


Prove the following identities:

`1/(cosA + sinA) + 1/(cosA - sinA) = (2cosA)/(2cos^2A - 1)`


`1+ (cot^2 theta)/((1+ cosec theta))= cosec theta`


`cos^2 theta /((1 tan theta))+ sin ^3 theta/((sin theta - cos theta))=(1+sin theta cos theta)`


If `sec theta + tan theta = p,` prove that

(i)`sec theta = 1/2 ( p+1/p)   (ii) tan theta = 1/2 ( p- 1/p) (iii) sin theta = (p^2 -1)/(p^2+1)`


\[\frac{1 - \sin \theta}{\cos \theta}\] is equal to


(sec A + tan A) (1 − sin A) = ______.


Prove the following identity : 

`1/(cosA + sinA - 1) + 2/(cosA + sinA + 1) = cosecA + secA`


Prove that :
2(sin6 θ + cos6 θ) − 3 (sin4 θ + cos4 θ) + 1 = 0


Prove that `(cos θ)/(1 - sin θ) = (1 + sin θ)/(cos θ)`.


If cot θ + tan θ = x and sec θ – cos θ = y, then prove that `(x^2y)^(2/3) – (xy^2)^(2/3)` = 1


Prove that `(sin^2theta)/(cos theta) + cos theta` = sec θ


Prove that `(tan(90 - theta) + cot(90 - theta))/("cosec"  theta)` = sec θ


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