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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

From the Figure Find the Value of Sinθ. - Geometry Mathematics 2

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प्रश्न

From the figure find the value of sinθ.

बेरीज

उत्तर

`sinθ = ("AB")/("AC")`

`sinθ = 3/5`

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2018-2019 (March) Balbharati Model Question Paper Set 1

संबंधित प्रश्‍न

Prove the following trigonometric identities.

`sin^2 A + 1/(1 + tan^2 A) = 1`


Prove the following trigonometric identities.

`tan^2 theta - sin^2 theta tan^2 theta sin^2 theta`


Prove the following trigonometric identities.

`sin A/(sec A + tan A - 1) + cos A/(cosec A + cot A + 1) = 1`


Prove the following trigonometric identities.

if x = a cos^3 theta, y = b sin^3 theta` " prove that " `(x/a)^(2/3) + (y/b)^(2/3) = 1`


Prove the following identities:

`secA/(secA + 1) + secA/(secA - 1) = 2cosec^2A`


Prove that:

2 sin2 A + cos4 A = 1 + sin4


Prove that:

`(cosecA - sinA)(secA - cosA) = 1/(tanA + cotA)`


`sin^2 theta + 1/((1+tan^2 theta))=1`


Write the value of `(1 + tan^2 theta ) cos^2 theta`. 


Eliminate θ, if
x = 3 cosec θ + 4 cot θ
y = 4 cosec θ – 3 cot θ


If \[\sin \theta = \frac{1}{3}\] then find the value of 2cot2 θ + 2. 


 Write True' or False' and justify your answer the following :

The value of the expression \[\sin {80}^° - \cos {80}^°\] 


If x = a cos θ and y = b sin θ, then b2x2 + a2y2 =


If sinA + cosA = m and secA + cosecA = n , prove that n(m2 - 1) = 2m


Prove that `sqrt((1 + sin A)/(1 - sin A))` = sec A + tan A. 


Prove that sec2 (90° - θ) + tan2 (90° - θ) = 1 + 2 cot2 θ.


Prove that `"cosec"  θ xx sqrt(1 - cos^2theta)` = 1


sin4A – cos4A = 1 – 2cos2A. For proof of this complete the activity given below.

Activity:

L.H.S = `square`

 = (sin2A + cos2A) `(square)`

= `1 (square)`       .....`[sin^2"A" + square = 1]`

= `square` – cos2A    .....[sin2A = 1 – cos2A]

= `square`

= R.H.S


The value of tan A + sin A = M and tan A - sin A = N.

The value of `("M"^2 - "N"^2) /("MN")^0.5`


Prove the following that:

`tan^3θ/(1 + tan^2θ) + cot^3θ/(1 + cot^2θ)` = secθ cosecθ – 2 sinθ cosθ


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