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प्रश्न
Integrate the functions:
`e^(tan^(-1)x)/(1+x^2)`
उत्तर
Let `I = int (e^(tan -1 x)/(1 + x^2))` dx
Put tan-1 x = t
`1/(1 + x^2)` dx = dt
Hence, `I = int e^t` dt
= et + C
= `e^(tan^-1) + C`
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