English

E and F are points on the sides PQ and PR, respectively, of a ΔPQR. For the following case, state whether EF || QR. PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.36 cm - Mathematics

Advertisements
Advertisements

Question

E and F are points on the sides PQ and PR, respectively, of a ΔPQR. For the following case, state whether EF || QR.

PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.36 cm

Sum

Solution

PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm, PF = 0.36 cm

`("PE")/("PQ") = 0.18/1.28 = 18/128 = 9/64`

`("PF")/("PR") = 0.36/2.56=9/64`

Hence, `("PE")/("PQ") = ("PF")/("PR")`

Therefore EF is parallel to QR.

shaalaa.com
  Is there an error in this question or solution?
Chapter 6: Triangles - Exercise 6.2 [Page 128]

APPEARS IN

NCERT Mathematics [English] Class 10
Chapter 6 Triangles
Exercise 6.2 | Q 2.3 | Page 128

RELATED QUESTIONS

In figure, ∆ACB ~ ∆APQ. If BC = 8 cm, PQ = 4 cm, BA = 6.5 cm, AP = 2.8 cm, find CA and AQ.


In figure, `\frac{AO}{OC}=\frac{BO}{OD}=\frac{1}{2}` and AB = 5 cm. Find the value of DC.


A vertical stick 20 cm long casts a shadow 6 cm long on the ground. At the same time, a tower casts a shadow 15 m long on the ground. Find the height of the tower.


In the following figure, if LM || CB and LN || CD, prove that `("AM")/("AB")=("AN")/("AD")`


`triangleDEF ~ triangleMNK`. If DE = 5 and MN = 6, then find the value of `(A(triangleDEF))/(A(triangleMNK))`


Given `triangle ABC ~ triangle PQR`, if `(AB)/(PQ) = 1/3`, then find `(ar  triangle ABC)/(ar triangle PQR)`


In the adjoining figure, ABC is a right angled triangle with ∠BAC = 90°.

1) Prove ΔADB ~ ΔCDA.

2) If BD = 18 cm CD = 8 cm Find AD.

3) Find the ratio of the area of ΔADB is to an area of ΔCDA.


In the given figure ABC is a triangle with ∠EDB = ∠ACB.  Prove that Δ ABC ~ Δ EBD. If BE = 6 cm, EC = 4 cm, BD = 5 cm. And area of Δ BED = 9 cm2. Calculate the

(1) length of AB
(2) area of Δ ABC


In ΔABC and ΔDEF, it is being given that: AB = 5 cm, BC = 4 cm and CA = 4.2 cm; DE=10cm, EF = 8 cm and FD = 8.4 cm. If AL ⊥ BC and DM ⊥ EF, find AL: DM.


In the given figure, AB || EF || DC; AB = 67.5 cm, DC = 40.5 cm and AE = 52.5 cm.

  1. Name the three pairs of similar triangles.
  2. Find the lengths of EC and EF.

The ratio between the corresponding sides of two similar triangles is 2 is to 5. Find the ratio between the areas of these triangles.


Area of two similar triangles are 98 sq. cm and 128 sq. cm. Find the ratio between the lengths of their corresponding sides.


The given diagram shows two isosceles triangles which are similar. In the given diagram, PQ and BC are not parallel; PC = 4, AQ = 3, QB = 12, BC = 15 and AP = PQ.


Calculate:

  1. the length of AP,
  2. the ratio of the areas of triangle APQ and triangle ABC.

In each of the given pairs of triangles, find which pair of triangles are similar. State the similarity criterion and write the similarity relation in symbolic form: 

 


In each of the given pairs of triangles, find which pair of triangles are similar. State the similarity criterion and write the similarity relation in symbolic form: 

 


ΔABC~ΔDEF and their areas are respectively 64 cm2 and 121cm2. If EF = 15.4cm, find BC. 


ΔABC ~ ΔDEF and their areas are respectively `100cm^2` and `49cm2`. If the altitude of ΔABC is 5cm, find the corresponding altitude of ΔDEF.


In ΔABC, D and E are the midpoints of AB and AC respectively. Find the ratio of the areas of ΔADE and ΔABC. 

 


Select the appropriate alternative.
In ∆ABC and ∆PQR, in a one to one correspondence \[\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ}\] 


 In ∆ABC and ∆DEF ∠B = ∠E, ∠F = ∠C and AB = 3DE then which of the statements regarding the two triangles is true ?


In the given figure, seg XY || seg BC, then which of the following statements is true?


In the figure, parts of the two triangles bearing identical marks are
congruent. State the test by which the triangles are congruent.


Prove that the area of  Δ BCE described on one side BC of a square ABCD is one half the area of the similar Δ ACF described on the diagonal AC. 


In  Δ ABC, DE || BC; DC and EB intersects at F. if `"DE"/"BC" = 2/7` , find `("Ar" (triangle "FDE"))/("Ar" (triangle "FBC"))`


Δ ABC is similar to Δ PQR. If AB = 6cm, BC = 9cm, PQ = 9cm and PR = 10.5cm, find the lengths of AC and QR.


ABCD and PQRS are similar figures. AB= 12cm, BC=x cm, CD= 15 cm, AD= 10 cm, PQ= 8 cm, QR = 5 cm, RS = m cm and PS = n cm .Find the values of x, m and n. 


Δ ABC  ∼ Δ PQR such that AB= 1.5 cm and PQ=2. 1 cm. Find the ratio of areas of Δ ABC and  ΔPQR.


A model of a ship is made with a scale factor of 1 : 500. Find

The deck area of the model, if the deck area of the ship is 1500000 m2  


The scale of a map is 1 : 200000. A plot of land of area 20km2 is to be represented on the map. Find

The area on the map that represents the plot of land. 


A triangle LMN has been reduced by scale factor 0.8 to the triangle L' M' N'. Calculate: the length of M' N', if MN = 8 cm.


In the following figure, point D divides AB in the ratio 3 : 5. Find :

DE = 2.4 cm, find the length of BC.


In ΔABC, D and E are the mid-point on AB and AC such that DE || BC.
If AD = 4, AE = 8, DB = x - 4 and EC = 3x - 19, find x.


In ΔABC, MN is drawn parallel to BC. If AB = 3.5cm, AM : AB = 5 : 7 and NC = 2cm, find:
(i) AM
(ii) AC


ABCD is a parallelogram whose sides AB and BC are 18cm and 12cm respectively. G is a point on AC such that CG : GA = 3 : 5 BG is produced to meet CD at Q and AD produced at P. Prove that ΔCGB ∼ ΔAGP. Hence, fi AP.


AM and DN are the altitudes of two similar triangles ABC and DEF. Prove that: AM : DN = AB : DE.


In the given figure, PB is the bisector of ABC and ABC =ACB. Prove that:
a. BC x AP = PC x AB
b. AB:AC = BP: BC


Harmeet is 6 feet tall and casts a shadow of 3 feet long. What is the height of a nearby pole if it casts a shadow of 12 feet long at the same time?


Find the scale factor in each of the following and state the type of size transformation:
Image length = 6cm, Actual length = 4cm.


The scale of a map is 1 : 50000. The area of a city is 40 sq km which is to be represented on the map. Find: The length of a scale in km represented by 1cm on the map.


A plot of land of area 20km2 is represented on the map with a scale factor of 1:200000. Find: The ground area in km2 that is represented by 2cm2 on the map.


A plot of land of area 20km2 is represented on the map with a scale factor of 1:200000. Find: The area on the map that represented the plot of land.


A model of a ship is made to a scale of 1:500. Find: The area other deck o the ship, if the area of the deck of its model is m2


On a map drawn to a scale of 1:25000, a triangular plot of land is right angled and the sides forming the right angle measure 225cm and 64cm.Find: The area of the plot in sq. km.


In a triangle ABC, AB = 4 cm, BC = 4.5 cm and CA = 5 cm. Construct ΔABC. Find the image A'B'C of the ΔABC obtained by enlarging it by a scale factor 2. Measure the sides of the image A'B'C' and show that AB:A'B' = AC:B'C' = CA:C'A'


If figure OPRQ is a square and ∠MLN = 90°. Prove that ∆QMO ~ ∆RPN


Construct a triangle similar to a given triangle ABC with its sides equal to `6/5` of the corresponding sides of the triangle ABC (scale factor `6/5 > 1`)


If BD ⊥ AC and CE ⊥ AB, prove that `"CA"/"AB" = "CE"/"DB"`


In the given figure YH || TE. Prove that ΔWHY ~ ΔWET and also find HE and TE


From the figure, prove that ∆SUN ~ ∆RAY


ΔPQR ~ ΔSUV. Write pairs of congruent angles


Side of equilateral triangle PQR is 8 cm then find the area of triangle whose side is half of the side of triangle PQR.


In the given figure the value of x is 


Is the following statement true? Why? “Two quadrilaterals are similar, if their corresponding angles are equal”.


In the given figure, ΔABC ∼ ΔQPR, If AC = 6 cm, BC = 5 cm, QR = 3 cm and PR = x; them the value of x is ______.


In ΔABC, PQ || BC. If PB = 6 cm, AP = 4 cm, AQ = 8 cm, find the length of AC.


In the given figure, if ABCD is a trapezium in which AB || CD || EF, then prove that `(AE)/(ED) = (BF)/(FC)`.


In figure, if AD = 6 cm, DB = 9 cm, AE = 8 cm and EC = 12 cm and ∠ADE = 48°. Find ∠ABC. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×