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Question
Evaluate the following:
`cos^-1{cos ((4pi)/3)}`
Solution
We know
`cos^-1(costheta)=thetaif 0<=theta<=pi`
We have
`cos^-1{cos ((4pi)/3)}=cos^-1{cos(2pi-(2pi)/3)}`
`=cos^-1{cos((2pi)/3)}`
`=(2pi)/3`
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