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Question
Evaluate the following:
`tan^-1(tan (7pi)/6)`
Solution
We know that
`tan^-1(tantheta)=theta, -pi/2<theta<pi/2`
We have
`tan^-1(tan (7pi)/6)=tan^-1[tan(pi+pi/6)]`
`=tan^-1[tan(pi/6)]`
`=pi/6`
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