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Question
Factorise the following:
16x2 + 4y2 + 9z2 – 16xy – 12yz + 24xz
Solution
16x2 + 4y2 + 9z2 – 16xy – 12yz + 24xz
= (4x)2 + (–2y)2 + (3z)2 + 2(4x)(–2y) + 2(–2y)(3z) + 2(4x)(3z) ...[Using identity, (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca]
= (4x – 2y + 3z)2
= (4x – 2y + 3z)(4x – 2y + 3z)
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