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Question
Find the area bounded by the curve y = sinx between x = 0 and x = 2π.
Solution
Required area = `int_0^pi sinx "d"x + int_pi^(2pi) |sin x|"d"x`
= `-[cos x]_0^pi + |(- cos x)|_pi^(2pi)`
= `=[cos pi - cos 0] + [cos 2pi - cos pi]`
= `-[-1 - 1] + [1 + 1]`
= 2 + 2
= 4 sq.units
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